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Kryger [21]
3 years ago
13

The height of a model rocket is 4.5% of the height of the actual rocket.The model is 1.22 m high.How high is the actual rocket

Mathematics
1 answer:
Serjik [45]3 years ago
6 0

Answer:

Actual Height = 27.11 m

Step-by-step explanation:

Given:

Height of model rocket = 4.5 % of actual Height

Model Height = 1.22 m

To Find:

Actual Height of rocket = ?

Solution:

We have to Find the Actual Height of the rocket

Let actual height be x

Now it is given that

Height of model rocket = 4.5 % of actual Height

As we have the values so putting it in it becomes

1.22 = 4.5 % * x

it could be written as

1.22=\frac{4.5}{100}*x

Multiplying both sides by \frac{100}{4.5}

it becomes

1.22*\frac{100}{4.5} = x

\frac{122}{4.5} = x

27.11 m =x

or

Actual Height = 27.11 m

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In a Calculus class, there are 11 freshman and 15 sophomores; 5 of the sophomores are females,
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61.5%

Step-by-step explanation:

Let's find all the demographics first:

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Solve the problem. Use the Central Limit Theorem.The annual precipitation amounts in a certain mountain range are normally distr
bazaltina [42]

Answer:

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 109.0 inches, and a standard deviation of 12 inches.

This means that \mu = 109, \sigma = 12

Sample of 25.

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This is the p-value of Z when X = 112. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{112 - 109}{2.4}

Z = 1.25

Z = 1.25 has a p-value of 0.8944.

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

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