Hey there __________ The correct answer is Whatever each CD costs, what each person paid is that cost times the number of CDs purchased (no sales tax for this problem). So, the price of one CD is a factor of $66 (a number of $ that divides $66 evenly). In theory, it could be $1, $2, $3, $6, $11, $22, $66. It could even be $0.50, $0.25, $0.20, $0.10, $0.05,... Also, the price of one CD must be a factor of $54. such as $54,$27,$18,$9,$6,$3,$2,$1,... . You are looking for the most that price could be.
The grew greatest price that is in both lists is $6.
How can you make those lists? You can start with the total price, then the price divided by 2, by 3, by whatever whole number you can divide it.
Otherwise, you could find the greatest common factor of 66 and 54 from the prime factorization of both numbers. ___________________ Hope this helps you
The right statistical procedure is by applying a hypothesis test that uses a single mean. Here, if we are to talk about comparison, it should be between the mean IQ of the students in the class and the national average IQ. The class is not for a comparison between two population means because it is viewed as the sample of the population. That is to say, the required task is to determine if the sample mean is greater than the population mean. We can conclude that this obeys a hypothesis test rather than a confidence interval.
you're simply being asked to, approximate the area, by using 4 rectangles, like in the graph, it doesn't have to be an exact value, just an approximation, based on the width and height of the rectangles, and getting their area by that
those rectangles are 0.39 radian long, since if you split π/2 in 4 pieces, you get around that much, the last rectangle there is a bit smaller than 0.39.... but they don't have to be 4 rectangles of equal length
so, get the area of the rectangles, based on their width and height, and sum them up