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steposvetlana [31]
3 years ago
12

At CD Shack, all used CDs are the same price. Jesse spent $54 and Mimi spent $66 on used CDs. What is the most each used CD coul

d cost?
Mathematics
1 answer:
Alinara [238K]3 years ago
5 0
Hey there
__________
The correct answer is
Whatever each CD costs, what each person paid is that cost times the number of CDs purchased (no sales tax for this problem).
So, the price of one CD is a factor of $66 (a number of $ that divides $66 evenly).
In theory, it could be $1, $2, $3, $6, $11, $22, $66.
It could even be $0.50, $0.25, $0.20, $0.10, $0.05,...
Also, the price of one CD must be a factor of $54. such as $54,$27,$18,$9,$6,$3,$2,$1,... .
You are looking for the most that price could be.


The grew greatest price that is in both lists is $6.

How can you make those lists?
You can start with the total price, then the price divided by 2, by 3, by whatever whole number you can divide it.

Otherwise, you could find the greatest common factor of 66 and 54
from the prime factorization of both numbers.
___________________
Hope this helps you
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Points A, B, and C are collinear. Point B is between A and C. BC=8x+709. AB=487+5x. AC=91. Find BC.
Zolol [24]

Answer:

<h3>            BC = 29</h3>

Step-by-step explanation:

Point B is between A and C and the points A, B, and C are collinear so:

AB + BC = AC

487 + 5x + 8x + 709 = 91

  13x + 1196 = 91

       - 1196      - 1196

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