Answer:
3
Step-by-step explanation:
Define the range of a list of numbers.
<em>I'm not %100 percent certain because I learned that a long time ago.</em>
Answer:
4.75% probability that the line pressure will exceed 1000 kPa during any measurement
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that the line pressure will exceed 1000 kPa during any measurement
This is 1 subtracted by the pvalue of Z when X = 1000. So



has a pvalue of 0.9525
1 - 0.9525 = 0.0475
4.75% probability that the line pressure will exceed 1000 kPa during any measurement
1st integer: x
2nd integer: x+2
Multiply them: x(x+2)=440
X^2+2x-440=0
Use the quadratic formula
x=-22 or x=20
Since x must be a positive integer number, x=20.
Answer:
1st: 20.
2nd: 22
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Answer:
The probability of randomly selecting a rod that is shorter than 22 cm
P(X<22) = 0.1251
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given mean of the Population = 25cm
Given standard deviation of the Population = 2.60
Let 'x' be the random variable in normal distribution
Given x=22

<u><em>Step(ii):</em></u>-
The probability of randomly selecting a rod that is shorter than 22 cm
P(X<22) = P( Z<-1.15)
= 1-P(Z>1.15)
= 1-( 0.5+A(1.15)
= 0.5 - A(1.15)
= 0.5 - 0.3749
= 0.1251
The probability of randomly selecting a rod that is shorter than 22 cm
P(X<22) = 0.1251
Answer:
it would be on y-4.
and there is no x coordinate because it's 0