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Igoryamba
3 years ago
10

Jenny has saved $600 from her summer job. During the school year, she withdraws $20 from her account every week for her daily ex

penses. She wants to keep more than $300 in the account for college. The number of weeks, w, that Jenny can withdraw money from her account is represented by the inequality 600 − 20w > 300. How many weeks can Jenny continue to withdraw $20 from her account?
14
17
20
22
Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
7 0
600 - 20w > 300
-20w > 300 - 600
-20w > - 300
20w < 300
w < 300/20
w < 15

Therefore, Jenny can withdraw $20 from her account for 14 weeks
IgorC [24]3 years ago
3 0

Answer:

14 weeks

Step-by-step explanation:

Given : The number of weeks, w, that Jenny can withdraw money from her account is represented by the inequality 600 − 20w > 300.

To Find: How many weeks can Jenny continue to withdraw $20 from her account?

Solution:

Expression: 600 − 20w > 300.

Now we are supposed to find for how many weeks can Jenny continue to withdraw $20 from her account.

So, 600 -20w > 300

-20w > 300-600

-20w

20w< 300

w

w

Thus jenny can continue for less than 15 weeks .

So, Option A is correct.

Hence Jenny can continue for 14 weeks to withdraw $20 from her account.

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In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,
aleksley [76]

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

6 0
4 years ago
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