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luda_lava [24]
2 years ago
15

Helpppppppppppppppppppp

Mathematics
2 answers:
Georgia [21]2 years ago
8 0
The answer would be 16.

Hope this helps! :)
stira [4]2 years ago
5 0

Answer:

16

Step-by-step explanation:

To find the area the formula is:

A =\frac{1}{2}bh

A = \frac{1}{2} 8units x 4units

A = \frac{1}{2}  32

A = 16

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Tpy6a [65]
The number between 4 and -7 is -3/2, so no, the answer is (2, -3/2) which is B
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Help<br> What is an equation of the line that passes through the points (-4, 4) and (8.1)?
Svetach [21]

Answer:

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Step-by-step explanation:

Hope this helps!

3 0
3 years ago
A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data
Rasek [7]

Answer: a. 1.981 < μ < 2.18

              b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

\overline{x}=\frac{\Sigma x}{n}

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Now, we estimate standard deviation:

s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }

s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }

s = 0.1564

For t-score, we need to determine degree of freedom and \frac{\alpha}{2}:

df = 12 - 1

df = 11

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Then, t-score is

t_{11,0.025} = 2.201

The interval will be

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2.08 ± 2.201\frac{0.1564}{\sqrt{12} }

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

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3 years ago
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katen-ka-za [31]

You just have to choose the middle one

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3 years ago
Determine the product. 800.5 x (2x10^6)
zhenek [66]
D. 10^6 = 1000000 x 2 = 2000000 x 800.5 = 1601000000 = 1.601 x 10^9
6 0
2 years ago
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