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8090 [49]
3 years ago
8

There are two similar right triangles. One has side lengths of 6, 8, and 10. The other has side lengths of 24, and 18. What is t

he length of the missing side?
Mathematics
1 answer:
maxonik [38]3 years ago
3 0

Answer:

30

Step-by-step explanation:

24/8 = 3

18/6= 3

10x3 = 30

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An Information Services Manager is purchasing a large number of word processing software licenses at a cost of $125 each. the so
dangina [55]

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143

Step-by-step explanation:

17300=.965(125X)

17927.46=125X

143.41=X

4 0
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La sombra que proyecta un edificio es de 16 m si el coseno del ángulo que se forma entre la punta de la sombra y el techo del ed
AlekseyPX

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Step-by-step explanation:

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6 0
3 years ago
X=5 then x + 6 <br><br> Pls help
serious [3.7K]

Answer:

11

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
5a - 24b =-15<br> 10a + 45c =21<br> 48b + 35c = 49
andrew-mc [135]

5a + 15 = 24b so,

10a + 30 = 48b,

sub to third equation,

10a + 30 + 35c = 49

10a + 35c = 19

perform elimination with second equation

10a + 45c = 21

10a + 35c = 19

________________-

10c = 2

c = 1/5

sub to second equation,

10a + (45)(1/5) = 21

10a + 9 = 21

10a = 12

a = 6/5

sub to first equation

(5)(6/5) - 24b = -15

6 + 15 = 24b

21 = 24b

b = 7/8

redo the calculations, correct me if I'm wrong

6 0
3 years ago
The length of some fish are modeled by a von Bertalanffy growth function. For Pacific halibut, this function has the form L(t) =
Dafna1 [17]

Answer:

a) L'(t) = 34.416*e^(-0.18*t)

b) L'(0) = 34 cm/yr , L'(1) =29 cm/yr , L'(6) =12 cm/yr

c) t = 10 year                                          

Step-by-step explanation:

Given:

- The length of fish grows with time. It is modeled by the relation:

                                   L(t) = 200*(1-0.956*e^(-0.18*t))

Where,

L: Is length in centimeter of a fist

t: Is the age of the fish in years.

Find:

(a) Find the rate of change of the length as a function of time

(b) In this part, give you answer to the nearest unit. At what rate is the fish growing at age: t = 0 , t = 1, t = 6

c) When will the fish be growing at a rate of 6 cm/yr? (nearest unit)

Solution:

- The rate of change of length of a fish as it ages each year  can be evaluated by taking a derivative of the Length L(t) function with respect to x. As follows:

                             dL(t)/dt = d(200*(1-0.956*e^(-0.18*t))) / dt

                             dL(t)/dt = 34.416*e^(-0.18*t)

- Then use the above relation to compute:

                            L'(t) = 34.416*e^(-0.18*t)

                            L'(0) = 34.416*e^(-0.18*0) = 34 cm/yr

                            L'(1) = 34.416*e^(-0.18*1) = 29 cm/yr

                            L'(6) = 34.416*e^(-0.18*6) = 12 cm/yr

- Next, again use the derived L'(t) to determine the year when fish is growing at a rate of 6 cm/yr:

                             6 cm/yr = 34.416*e^(-0.18*t)

                             e^(0.18*t) = 34.416 / 6

                             0.18*t = Ln(34.416/6)

                             t = Ln(34.416/6) / 0.18

                             t = 10 year

7 0
3 years ago
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