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3 years ago

7

What type of line is represented by the equation x=6

1 answer:

Vaselesa [24]3 years ago

7 0

It represented a vertical line that no matter what y is, x is always 6

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A money bag contains ten 5-dollar notes and thirty 10-dollar notes. If a note is randomly selected from the bag, what is the pro

lapo4ka [179]

Not a 5 dollar just means a 10 dollar

probblity=desired outcomes/total possible outcomes

desired=number of 10 dollar notes or 30

total possible=10+30 or 40

the probablity is 30/40 or 3/4 or 75% that you do not select a 5 dollar note

4 0

3 years ago

Solve for x: 3x − 2 > 5x + 10. (5 points)<br> 1) x > 6<br><br> 2) x −6

san4es73 [151]

Answer:

$x$

Step-by-step explanation:

$3x-2>5x+10$

Add 2 to both sides

$3x-2+2>5x+10+2$

Simplify

$3x>5x+12$

Subtract $5x$ from both sides

$3x-5x>5x+12-5x$

Simplify

$-2x>12$

Multiply both sides by $-1$ (reverse the inequality)

$(-2x)(-1)$

Simplify

$2x$

Divide both sides by $2$

$\frac{2x}{2}$

Divide the numbers: $\frac{2}{2} =1$

$=x$

Divide the numbers: $\frac{-12}{2}$

Apply fraction rule: $\frac{-a}{b} =-\frac{a}{b}$

$=\frac{12}{2}$

Divide the numbers: $\frac{12}{2} =6$

$=-6$

$x$

7 0

3 years ago

Read 2 more answers

A 3 liter bottle of juice costs $5.70<br> What is the unit price for 1 liter of juice?

Galina-37 [17]

Answer:

$1.90

Step-by-step explanation:

Divide 5.7 by 3 to get your answer.

$\frac{5.7}{3}$ = 1.9

3 0

3 years ago

Read 2 more answers

Solve for the roots in the equation below. In your final answer, include each of the necessary steps and calculations.

Nostrana [21]

$x^3-27i=0$
$x^3=27i$
$x^3=27e^{i\pi/2}$
$x=\left(27e^{i\pi/2}\right)^{1/3}$
$x=3e^{i(\pi/2+2\pi k)/3}$
$x=3e^{i\pi(4k+1)/6}$

where $k\in\{0,1,2\}$ . This means you have

$x=3e^{i\pi/6}=\dfrac32(\sqrt3+i)$
$x=3e^{i5\pi/6}=\dfrac32(-\sqrt3+i)$
$x=3e^{i9\pi/6}=-3i$

as the solutions to the original equation.

4 0

3 years ago

How to do math easily

katrin [286]

Step-by-step explanation:

Keep quit when they a teaching you and stay with participanting people/friends

7 0

2 years ago