Answer:
a.) The sum of the weights of the two in insects is 0.0031 grams. (0.0031 grams)
b.) The fly is 0.0013 grams heavier than the gnat. (0.0013 grams)
Step-by-step explanation:
2.2 * 10^-3 = 2.2 * 1/1000 which is 2.2/1000.
9 * 10^-4 = 9 * 1/10000 = 9/10000
To add 9/10000 to 2.2/1000 we have to find the common denominator, which will be 10000.
So we do:
2.2/1000 * 10/10 = 22/10000
9/10000 + 22/10000 = 31/10000 = 0.0031.
The sum of the weights of the two in insects is 0.0031 grams.
To find how much heavier the fly is than the gnat we do:
22/10000 - 9/10000 = 13/10000 = 0.0013
The fly is 0.0013 grams heavier than the gnat.
An=A1+(n-1)d
-20=A1+(15-1)x-7
-20=A1+14 x -7
-20=A1-98
+98 +98
-98+98=0
-20+98=78
A1=78
Each table is $6
Each chair costs $2.50
if correct please give<span> brainliest
Thankyou :)</span>
I think the answer is a. because all sides are the same.
1 side = 38
side m = probably 38
Hope this helped☺☺
Let P be Brandon's starting point and Q be the point directly across the river from P.
<span>Now let R be the point where Brandon swims to on the opposite shore, and let </span>
<span>QR = x. Then he will swim a distance of sqrt(50^2 + x^2) meters and then run </span>
<span>a distance of (300 - x) meters. Since time = distance/speed, the time of travel T is </span>
<span>T = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x). Now differentiate with respect to x: </span>
<span>dT/dx = (1/4)*(2500 + x^2)^(-1/2) *(2x) - (1/6). Now to find the critical points set </span>
<span>dT/dx = 0, which will be the case when </span>
<span>(x/2) / sqrt(2500 + x^2) = 1/6 ----> </span>
<span>3x = sqrt(2500 + x^2) ----> </span>
<span>9x^2 = 2500 + x^2 ----> 8x^2 = 2500 ---> x^2 = 625/2 ---> x = (25/2)*sqrt(2) m, </span>
<span>which is about 17.7 m downstream from Q. </span>
<span>Now d/dx(dT/dx) = 1250/(2500 + x^2) > 0 for x = 17.7, so by the second derivative </span>
<span>test the time of travel, T, is minimized at x = (25/2)*sqrt(2) m. So to find the </span>
<span>minimum travel time just plug this value of x into to equation for T: </span>
<span>T(x) = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x) ----> </span>
<span>T((25/2)*sqrt(2)) = (1/2)*(sqrt(2500 + (625/2)) + (1/6)*(300 - (25/2)*sqrt(2)) = 73.57 s.</span><span>
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</span><span>mind blown</span>
