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shepuryov [24]
3 years ago
10

A rectangle has a fun property. The value of its perimeter is equal to the value of its area. The rectangle has a length of 2x f

eet and a width of 3 feet. 1. Write the equation perimeter equals to the area. 2. Solve for 'x' 3. Write both the value of the perimeter and the value of the area.
Mathematics
1 answer:
Reika [66]3 years ago
3 0

Answer:

1) 6\cdot x = 4\cdot x+6, 2) The value of x is 3, 3) The perimeter and the area of the rectangule are 18 feet and 18 square feet, respectively.

Step-by-step explanation:

Let be a rectangle with a length of 2\cdot x feet and a width of 3 feet. The area (A), measured in square feet, and perimeter (p), measured in feet, formulas are, respectively:

A = (2\cdot x)\cdot (3)

A = 6\cdot x (Eq. 1)

p = 4\cdot x + 6 (Eq. 2)

1) Now, we assume that p = A, then we reduce the system of linear equation into a sole linear equation:

6\cdot x = 4\cdot x+6 (Eq. 3)

2) We proceed to solve for x:

2\cdot x = 6

x = 3

The value of x is 3.

3) Lastly, we obtain the values of the perimeter and area:

A = 6\cdot (3)

A = 18\,ft^{2}

p = 4\cdot (3)+6

p = 18\,ft

The perimeter and the area of the rectangule are 18 feet and 18 square feet, respectively.

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There are 16 kids on a soccer team. The players are either boys or girls, and they either prefer playing offense or defense. The
Mariana [72]

Answer:

P(B|A)=\frac{2}{7}

Step-by-step explanation:

The probability of P(B|A) can be read as the probability of event B occurring given event A. In this question, event A occurs when the chosen player is a girl. There are 7 girls on the soccer team. Event B occurs when the chose player plays defense. Since P(B|A) stipulates that event A already occurred, we want the probability of choosing a player who prefers defense from the 7 girls. There are 2 girls who prefer defense, hence P(B|A)=\boxed{\frac{2}{7}}.

<u>Alternative:</u>

For dependent events A and B, the conditional probability of event B occurring given A is given by:

P(B|A)=P(B\cap A)\div P(A)

P(B\cap A) indicates the intersection of P(B) and P(A). In this case, it is the probability that both events occur. Since there are 16 kids on the soccer team and only 2 are girls and prefer defense, P(B\cap A)=\frac{2}{16}=\frac{1}{8}. The probability of event A occurring (chosen player is a girl) is equal to the number of girls (7) divided by the number of kids on the team (16), hence P(A)=\frac{7}{16}.

Therefore, the probability of event B occurring, given event A occurred, is equal to:

P(B|A)=\frac{1}{8}\div \frac{7}{16},\\\\P(B|A)=\frac{1}{8}\cdot \frac{16}{7}=\boxed{\frac{2}{7}}

5 0
3 years ago
Hey,can you help me again?
tatiyna
Because the diameter is 47 cm

so the radius is 2x

r = 94 cm

A = πr² / 2

A = (3.14) (94)² / 2

A = 13872.52 cm²
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3 years ago
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