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Vladimir79 [104]
3 years ago
15

0.25 + 1 + 4 + 16 + 64 Enter the values used in finding a partial sum.

Mathematics
2 answers:
Deffense [45]3 years ago
6 0
This is a geometric series

r = 4
a1 = 0.25
n = 5
Alexeev081 [22]3 years ago
4 0

Answer:  The required values are

r=4,~~a_1=0.25~~\textup{and}~~n=5.

Step-by-step explanation:  We are given a partial sum as follows :

0.25 + 1 + 4 + 16 + 64.

We are to find the values of r,~~a_1~~\textup{and}~~n.

From the given partial series, we note that

the series is a geometric one with first term 0.25 and common ratio calculated as follows :

r=\dfrac{1}{0.25}=\dfrac{4}{1}=\dfrac{16}{4}=\dfrac{64}{16}=4.

Also, since there are 5 terms in the given sum, so the value of n is 5.

Thus, the required values are

r=4,~~a_1=0.25~~\textup{and}~~n=5.

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Solve the following probability problem. Give the answer in a
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Step-by-step explanation:

The probability of not selecting green or yellow marble is equal to the probability of selecting red and blue marble

n(S) =17

n(A)=5 (red)

n(B)=6 (blue)

answer is 5+6/17

=11/17

8 0
3 years ago
What is the value of x
fenix001 [56]

(2x+2) = (3x-52)

2x = 3x-54

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6 0
3 years ago
Tristan has some dimes and some quarters. He has at least 20 coins worth at most $4.25 combined. If Tristan has 10 dimes, determ
Dovator [93]

Answer:

The maximum number of quarters that he could have is 13

Step-by-step explanation:

Let x represent the number of quarters he could have. If he has 10 dimes and has at least 20 coins, then

→ x + 10 >= 20

→ x >= 10    (1)

His coins worth at most $4.25. Also, it is known that 1 dollar is equal to 100 cents, 1 dime is equal to 10 cents and 1 quarter is equal to 25 cents.

→ (x * 25) + (10 * 10)  <= (4.25 * 100)

→ 25x  + 100 <= 425

→ 25x <= 325

→ x <= 13  (2)

If we combine the equation 1 and 2:

10 <= x <= 13

The maximum value of x is 13

7 0
3 years ago
PLEASE PLEASE PLEASE HELP!!
Ivanshal [37]
Problem 1) The triangles are similar because of the AA (angle angle) Similarity Theorem. The first A is the pair of congruent 39 degree angles. The second pair is unmarked, but look at where the triangles meet. They form a pair of vertical angles which are congruent. So we have two pairs of congruent angles allowing us to use the AA Similarity Theorem.

-----------------------------

Problem 2) We can use the SAS (Side Angle Side) Similarity Theorem to prove that these two triangles are similar. The angles are congruent. They are both 29 degrees. So that checks off the "A" portion of SAS. Then notice how the bottom sides are 32 and 64 for the small and large triangle respectively. They form the ratio 32/64 = 1/2, ie the smaller triangle's side is 1/2 as long as the longer counter part. Similarly, 8/16 = 1/2 as well. The ratio is constant at 1/2. This allows us to use the other "S" portions of SAS. 
4 0
3 years ago
Please answer this question and thank you for your help
lions [1.4K]
The correct anwser is C.) (2,4)
5 0
3 years ago
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