Question

In the triangle below, what is cos B?

Answer 1

Cos B = c/a

cosine is adjacent over hypotenuse.


there is an acronym for this: soh-cah-toa

soh: sine is opposite over hypotenuse
cah: cosine is adjacent over hypotenuse
toa: tangent is opposite over adjacent

Answer 2

Answer:

$\text{cos}(B)=\frac{c}{a}$

Step-by-step explanation:

We have been given a triangle. We are asked to find $\text{cos}(B)$.

We know that cosine relates adjacent side of a right triangle to its hypotenuse.

$\text{cos}=\frac{\text{Adjacent}}{\text{Hypotenuse}}$

We can see that side AB is adjacent side and CB is hypotenuse of our given right triangle.

$\text{cos}(B)=\frac{AB}{CB}$

$\text{cos}(B)=\frac{c}{a}$

Therefore, our required value is $\text{cos}(B)=\frac{c}{a}$