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igomit [66]
4 years ago
13

In the triangle below, what is cos B?

Mathematics
2 answers:
Kruka [31]4 years ago
7 0
Cos B = c/a

cosine is adjacent over hypotenuse.


there is an acronym for this: soh-cah-toa

soh: sine is opposite over hypotenuse
cah: cosine is adjacent over hypotenuse
toa: tangent is opposite over adjacent
MAXImum [283]4 years ago
6 0

Answer:

\text{cos}(B)=\frac{c}{a}

Step-by-step explanation:

We have been given a triangle. We are asked to find \text{cos}(B).

We know that cosine relates adjacent side of a right triangle to its hypotenuse.

\text{cos}=\frac{\text{Adjacent}}{\text{Hypotenuse}}

We can see that side AB is adjacent side and CB is hypotenuse of our given right triangle.

\text{cos}(B)=\frac{AB}{CB}

\text{cos}(B)=\frac{c}{a}

Therefore, our required value is \text{cos}(B)=\frac{c}{a}

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