Answer:
49.92 miles/hour
Step-by-step explanation:
32 miles/hour = 32 * 5280 = 168960 ft/hour
For the collision to occur, both cars must arrive at the intersection at the same time.
The time it takes for the Mercedes to travel 400 feet at the rate of 168960 ft/hour is 400 / 168960 = 0.002367 hours
So the Ferrari should take the same time to travel 624 feet as well, its speed would be
624 / 0.002367 = 263577.6 ft/hour or 263577.6 / 5280 = 49.92 miles/hour
I think it is, I have no clue.
Here's some examples though, 5 example of not well defined sets: - Number of fire damages. - Number of reported crime scenes. ... - Numbers of illegal settlers.
Red, blue, yellow, green, purple is well-defined since it is clear what is in the set.
Answer:
2,455
Step-by-step explanation:
Use PEMDAS to solve
First multiply 50x50, which is 2,500
50 x 50 + 60 - 105 becomes
2,500 + 60 - 105
Now to the addition or subtraction from left to right
2,560 - 105
2,455
Answer:
b
Step-by-step explanation:
Answer:
0.362
Step-by-step explanation:
When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:
- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.
- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14
- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7
- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.
Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability
P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362
