Let us always base on the present age. We denote this by x. Now, the age he had 2 years ago would then be denoted as (x-2). Let's equate this to 20 years old.
x - 2 = 20
x = 20 + 2
x = 22 years old
He should be 22 years old now.
Let's check the other condition. After 1 year, his age should be (x+1). Let's equate this to 23 years old.
x + 1 = 23
x = 23 - 1
x = 22
Thus, this is possible if Reuben is 22 years old as of the present.
Answer: 1.375 inches
Step-by-step explanation:
Answer:
Step-by-step explanation:
[1] 3x - 4y = -24
[2] -x - 16y = -52
Graphic Representation of the Equations :
-4y + 3x = -24 -16y - x = -52
Solve by Substitution :
// Solve equation [2] for the variable x
[2] x = -16y + 52
// Plug this in for variable x in equation [1]
[1] 3•(-16y+52) - 4y = -24
[1] - 52y = -180
// Solve equation [1] for the variable y
[1] 52y = 180
[1] y = 45/13
// By now we know this much :
x = -16y+52
y = 45/13
// Use the y value to solve for x
x = -16(45/13)+52 = -44/13
Solution :
{x,y} = {-44/13,45/13}
Answer:
a) 2.5% b) 84% c) 95% d) D. The more unusual day is if the stock closed below $185 because it has the largest absolute z-score.
Step-by-step explanation:
For a) b) and c) we will use the empirical rule, so, we can observe the image shown below
a) 211.23 is exactly two standard deviation above the mean, so, the probability that on a randomly selected day in this period the stock price closed above 211.23 is 2.35% + 0.15% = 2.5%
b) 204.11 represents exactly one standard deviation above the mean, so, the probability of being below 204.11 is 50% + 34% = 84%
c) The probability of getting a value between 182.75 and 211.23 is 95%, this because 182.75 is exactly two standard deviations below the mean and 211.23 is exactly two standard deviations above the mean.
d) The z-score related to 208 is
= (208-196.99)/7.12 = 1.5 and the z-score related to 185 is
= (185-196.99)/7.12 = -1.7, therefore, the more unusual day is if the stock closed below $185 because it has the largest absolute z-score.
Answer:
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