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Ronch [10]
3 years ago
11

A long distance runner starts at the beginning of a trail and runs at a rate of 6 miles per hour. One hour later, a cyclist star

ts at the beginning of the trail and travels at a rate of 14 miles per hour. What is the amount of time that the cyclist travels before overtaking the runner?
Mathematics
1 answer:
sasho [114]3 years ago
5 0
The answer to this is 50 minutes. by then the runner has gone 11 miles in an hour and 50min and the cyclist has gone 11 miles also 
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PLEASE HELP!
Wittaler [7]

Answer:

See below

Step-by-step explanation:

Use the formulae directly

For a cone, with base radius = r and height = h, here are the related formula

\textrm{Slant height  l} = \sqrt{r^2 + h^2}  (1)

\textrm{Lateral surface area} = \pi r l

\textrm {Base area} = \pi r^2

\textrm { Total Surface Area SA} = \textrm{Base Area + Lateral Area} = \pi r^2 + \pi rl = \pi r(r + l) (2)

\textrm{Volume V = } (1/3)  \pi r^2h (3)

Therefore directly plugging in the numbers in the above equations:

Note:

l = slant height in cm
SA = total surface area in sqcm
V = Volume in cubic cm

Figure(a)

r = 4, h = 8

\textrm{l} = \sqrt{4^2 + 8^2} =\sqrt{80} = 8.944 \\\textrm{SA}  = 4\pi(4 + 8.944) =  4\pi(12.944) = 162.66\\\textrm{V} = (1/3)\pi(4^2)(8) = 134.04

Figure(b)

r = 7, h =15

\textrm{l} = \sqrt{7^2 + 15^2} =\sqrt{274} = 16.55

\textrm{SA}  = 7\pi(7 + 16.55) =  517.89

Figure (c)

r = 5, l = 8

h = \sqrt{l^2 - r^2} = \sqrt{8^2 - 5^2} = \sqrt{39} = 6.245\\SA = \textrm{SA}  = 5\pi(5 + 8) =  204.2\\V = (1/3)\pi(5^2)(6.245) = 163.5


6 0
2 years ago
Please help I don’t understand this
horrorfan [7]

Answer:

C) 17

Step-by-step explanation:

Using the rule

A^2 + B^2 = C^2

8^2 + 15^2 = x^2

64 + 225 = x^2

x^2 = 289

x= _/-289

x = 17

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Oksana_A [137]

Answer:

0.25

Step-by-step explanation:

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Marco joined the soccer team and needs to buy new soccer shorts. He talks to a store owner who says the first pair will be $15 a
Licemer1 [7]

Answer:

4 pairs of shorts

Step-by-step explanation:

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