Your bedroom ceiling is 10 feet high and is 2/3 as high as the living room ceiling.

PLEASE HELP!! I WILL AWARD BRAINLIEST AND 50 POINTS!!!!!!!!!!!!!!!!!!!!!! For the given picture: a) List all of the triangles th

PIT_PIT [208]

Answer:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters. If your teacher just wants one, it would be the middle one. (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB. For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD. For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO. For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB. For OBF, it’s BOC and OCB

Step-by-step explanation:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters. If your teacher just wants one, it would be the middle one. (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB. For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD. For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO. For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB. For OBF, it’s BOC and OCB

6 0

3 years ago

Casey likes to.she runsan additional 1/4 mile each day. on the last day she ran 1 1/4 miles. if she ran 1/2 mile her first day f

bonufazy [111]

<span>1st day (2/4)
2nd day (3/4)
3rd day (4/4)
4th day 1 1/4 So she has been running for four days. ( I didnt know if you needed miles or not but, here you go ) <3</span>

3 0

3 years ago

10 1/2 divided by 3/8

gladu [14]

(10 1/2)/(3/8)
= (21/2)/(3/8) Convert to improper
= (21/2)*(8/3) Multiply by reciprocal of second
=(7/1)*(4/1) Cross reduce
=28 Multiply

5 0

2 years ago

I need help with this, please. Any advice would be appreciated.

mote1985 [20]

Answer:

see explanation

Step-by-step explanation:

The sum to n terms of an arithmetic sequence is

$S_{n}$ = $\frac{n}{2}$ [ 2a₁ + (n - 1)d ]

where a₁ is the initial value and d the common difference

Given

$S_{n}$ = $\frac{n}{2}$ [ 10 + (n - 1)3 ]

Then by comparison

2a₁ = 10 ( divide both sides by 2 )

a₁ = 4 ← initial value

and d = 3 ← common difference

Thus

$S_{8}$ = $\frac{8}{2}$ [ 10 + (7 × 3) ]

= 4(10 + 21)

= 4 × 31

= 124

8 0

3 years ago

ABC ~ ADE; find x <br> Pls help!!

Lubov Fominskaja [6]

Step-by-step explanation:

If ABC~ADE
then DE~BC

$\sf \rightarrowtail \: 2x + 3 = 15 \\ \sf \rightarrowtail \: 2x = 15 - 3 \\ \sf \rightarrowtail \: 2x = 12 \\ \sf \rightarrowtail \: x = \frac{12}{2} \\ \sf \rightarrowtail \: x = 6$

8 0

2 years ago