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kodGreya [7K]
3 years ago
13

Sami's boss asked him to cut 78⁄5 feet of rope to tie down a load on a truck. How much rope should Sami cut? A. 151⁄5 feet B. 16

feet C. 153⁄5 feet D. 152⁄3 feet
Mathematics
2 answers:
Paladinen [302]3 years ago
7 0

Answer:

The correct answer is 15\frac{3}{5} feet.

Step-by-step explanation:

The length of the rope Sami's boss asked him to cut is \frac{78}{5} feet.

Considering the given options, we need to rewrite the given fraction as a mixed number.

78=15\times5+3

This means that, the number of times 5 will divide 78 exactly, is 15, leaving a remainder of 3.


Hence, \frac{78}{5}=15\frac{3}{5}.


Therefore the correct answer is C.




Vitek1552 [10]3 years ago
5 0

how many times does 5 go into 78

78/5

it goes 15 times with  3 left over  (15*5 = 75  75+3 = 78)

15 3/5 ft

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Answer:

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Step-by-step explanation:

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3 years ago
The amount people pay for cable service varies quite a bit but the mean monthly fee is $142 and the standard deviation is $29. t
zhuklara [117]

Answer:

a) By the Central Limit Theorem, the mean is $142 and the standard deviation is $0.7488.

b) By the Central Limit Theorem, approximately normal.

c) 0.0901 = 9.01% probability that the average cable service paid by the sample of cable service customers will exceed $143

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean monthly fee is $142 and the standard deviation is $29.

This means that \mu = 142, \sigma = 29

Part a: what are the mean an standard deviation of the sample distribution of x hat show your work and justify your reasoning.

Sample of 1500(larger than 30).

By the Central Limit Theorem

The mean is $142

The standard deviation is s = \frac{29}{\sqrt{1500}} = 0.7488

Part b: what is the shape of the sampling distribution of x hat justify your answer.

By the Central Limit Theorem, approximately normal.

Part C: what is the probability that the average cable service paid by the sample of cable service customers will exceed $143?

This is 1 subtracted by the pvalue of Z when X = 143. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{143 - 142}{0.7488}

Z = 1.34

Z = 1.34 has a pvalue of 0.9099

1 - 0.9099 = 0.0901

0.0901 = 9.01% probability that the average cable service paid by the sample of cable service customers will exceed $143

4 0
3 years ago
Two ducklings wander away from the nest while their mother is away. The first duckling's displacement (distance and direction) f
aksik [14]

the second duckling is wandering by 2.6 units distance than the first duckling .

<u>Step-by-step explanation:</u>

Here we have , Two ducklings wander away from the nest while their mother is away. The first duckling's displacement (distance and direction) from the nest is (12,5) The second duckling's displacement is (13,-8) . We need to find How much farther did the second duckling wander than the first duckling. Let's find out:

Let a = (12,5) and b =(13,-8)

The distance each duckling wandered is the magnitude of its displacement vector. Therefore, the expression Distance second duck wandered is given by :

⇒ D  = |b|-|a|

⇒ D  = \sqrt{13^2+(-8)^2} -\sqrt{12^2+5^2}

⇒ D  = \sqrt{233} -\sqrt{169}

⇒ D  =15.26 -13

⇒ D  =2.6

Therefore , the second duckling is wandering by 2.6 units distance than the first duckling .

4 0
4 years ago
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