If the position at time <em>t</em> is
<em>s(t)</em> = (1 m/s³) <em>t</em> ³
then the average velocity over <em>t</em> = 2 s and <em>t</em> = 2.001 s is
<em>v</em> (ave) = (<em>s</em> (2.001 s) - <em>s</em> (2 s)) / (2.001 s - 2 s)
<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)
<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)
<em>v</em> (ave) ≈ 12.006 m/s
Answer:
5
Step-by-step explanation:
Answer:
the perimeter is 11cm and the area is 7cm^2
Step-by-step explanation:
NP =PS, meaning they have the same length. so the perimeter is 3.5 + 4 + another 3.5.
For the area imagine you cut the triangle in half. from P to the middle of NS. Put the 2 triangle halves together to form a rectangle. (PS is now touching NP). This would be a 2x 3.5 rectangle. 2x 3.5 is 7, meaning both this imagined rectangle and the triangle have an area of 7cm^2.
Answer:
shortest side = 15
Step-by-step explanation:
The question is a bit ambiguous. Do you mean (3/4) x or do you mean 3/(4x)?
I'll take it to be the first one.
(x + 3) + 4(x - 13) + (3/4)x = 3x + 6 Remove the brackets on the left
x + 3 + 4x - 52 + 0.75 x = 3x + 6 Combine
5.75x - 49 = 3x + 6 Subtract 3x from both sides.
2.75x - 49 = 6 Add 49 to both sides
2.75x = 55 Divide by 2.75
x = 55/ 2.75
x = 20
Now for the shortest side
x + 3 = 23
4(x - 13) = 4(20 - 13) = 4*7 = 28
(3/4)*20 = 15
The shortest side = 15
A and D are the correct answers