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belka [17]
4 years ago
5

What relationship is there between land area and the hemisphere with the greatest population density

Geography
1 answer:
timama [110]4 years ago
8 0
<span>Population density (in agriculture: standing stock and standing crop) is a measurement of population per unit area or unit volume; it is a quantity of type number density. It is frequently applied to living organisms, and most of the time to humans. It is a key geographical term Population density is population divided by total land area or water volume, as appropriate.</span>
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What is the advantage of volcano​
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A satellite orbiting earth has a tangential velocity of 5000 m/s. earth’s mass is kg and its radius is m. which is the distance
inessss [21]

The distance of the satellite form the earth is:
9,608,000 m (Option C) in Standard form, this is written as 9.6 x 10^{6}.

<h3>What is an Orbiting Satellite?</h3>

An Orbiting Satellite is a satellite that goes around the earth in an elliptical path known as an orbit.

To calculate the distance of the satellite from the earth we must equalize the force of Gravity to Centripetal Force given that these are the two forces that are at play here.

Step 1:

Equation that equalizes Gravity to Centripetality is:

G = mM/r² = m(v²/r)

Note that G = 6.67 x 10^{-11} (This is a gravitational constant.)

m is the Mass of the Satellite

M is Mass of the Earth

r is the distance of the satellite from the center of the earth

v is the satellites tangential velocity

Step 2 - Rearrange the formula and substitute the numbers above to get r

r = G (m/v²) = (6.67 x 10^{-11}) (6 x10^{24}/5000²) =

= 1.6 x 10^{7}m

Recall that form our postulation above, this is the satellites distance form the center of the earth.

To get it's distance form the earth's surface, we must know remove the value of the radius of the earth from the calculation. Where radius of the earth is given a r'

Hence,

r' = r - R = 1.6 x 10^{7}m - 6.4 x 10^{6}m

= 9.6 x 10^{6}m or 9,608,000 m

Learn more about orbiting satellites at:

brainly.com/question/18496962

3 0
2 years ago
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Hello There! ^-^ 

The altitude of the north celestial pole above the horizon is determined by the observer's _______________ on the Earth.

Your answer: The altitude of the north celestial pole above the horizon is determined by the observer's latitude on the Earth.

The answer is latitude.

~Hope this helps!




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Which of the following is true about radiation?
mars1129 [50]

Answer:

Option (4)

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