Question

Find the coordinates of point P along directed line segment AB with A(-4, 8) and B(16. - 2). so that the ratio of AP to PB is 3 to 2.
(82)
(63)
O (4.4)
0 (0.6

Answer 1

Answer:

P(8,2)

Explanation:

We can find the coordinates of P using section formula which is :

$(\dfrac{m_1x_2+m_2x_1}{m_1+m_2},\dfrac{m_1y_2+m_2y_1}{m_1+m_2})$

We have, m₁ = 3, m₂ = 2, x₁ = -4, y₁ = 8, x₂ = 16, y₂ = -2

Putting all the values, we get :

$(\dfrac{3\times 16+2\times (-4)}{3+2},\dfrac{3\times (-2)+2\times 8}{3+2})\\\\=(8,2)$

Hence, the coordinates of P is (8,2).