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quester [9]
3 years ago
5

HELP ASAPP!!!!!!!!

Mathematics
2 answers:
Drupady [299]3 years ago
8 0
37 feet is the length of the hypotenuse
jarptica [38.1K]3 years ago
4 0

Answer:

37

Step-by-step explanation:

Based on the points you gave, and the fact that your looking for the hypotenuse, we can assume that this is a right triangle with a 90 degree angle is at point C. Using pythag:

AB = \sqrt{35^{2}+12^{2}  } = 37

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Y=f(x)=2^x find f(x) when x=1
larisa86 [58]
f(x) = 2^x

When x = 1

f(1) = 2^{1} = 2

Answer : f(1) = 2
7 0
2 years ago
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( will give brainlyest)
Arada [10]

Answer: 384 feet

Step-by-step explanation:

     We will simplify and solve -16t² + 160t when t is equal to 4.

-16t² + 160t

-16(4)² + 160(4)

384 feet

8 0
1 year ago
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Please help! It's a final!!
Svetach [21]

Answer:

BBBBBBBBBB

Step-by-step explanation:

yeah if you add 2 without parenthesis it goes up

6 0
3 years ago
Find the indefinite integral. (Note: Solve by the simplest method—not all require integration by parts. Use C for the constant o
umka2103 [35]

Answer:

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2  ln⁡(1+x^2 )+C

Step-by-step explanation:

∫▒〖1st .2nd dx=1st∫▒〖2nd dx〗-∫▒〖(derivative of 1st) dx∫▒〖2nd dx〗〗〗

Let 1st=arctan⁡(x)

And 2nd=1

∫▒〖arctan⁡(x).1 dx=arctan⁡(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗

As we know that  

derivative of arctan(x)=1/(1+x^2 )

∫▒〖1 dx〗=x

So  

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-∫▒〖(1/(1+x^2 ))dx.x〗…………Eq1

Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now  

Let 1+x^2=u

du=2xdx

Multiply and divide ∫▒〖(1/(1+x^2 ))dx.x〗 by 2 we get

1/2 ∫▒〖(2/(1+x^2 ))dx.x〗=1/2 ∫▒(2xdx/u)  

1/2 ∫▒(2xdx/u) =1/2 ∫▒(du/u)  

1/2 ∫▒(2xdx/u) =1/2  ln⁡(u)+C

1/2 ∫▒(2xdx/u) =1/2  ln⁡(1+x^2 )+C

Putting values in Eq1 we get

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2  ln⁡(1+x^2 )+C  (required soultion)

3 0
3 years ago
Read 2 more answers
Rectangle LMNP is transformed to rectangle L'M'N'P' as shown on the graph below.
olganol [36]

9514 1404 393

Answer:

  2

Step-by-step explanation:

Each image point is twice as far from the origin as its preimage point. Each image segment is twice as long as its preimage segment. (LM=2, L'M'=4, for example)

The scale factor is 2.

3 0
3 years ago
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