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4 years ago

13

How do you solve -5y-6y=-22

1 answer:

Wewaii [24]4 years ago

5 0

-5y-6y is -11y=-22 so y=2

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What is a real world provlem tjat involves dividing a decimal by a whole number?

Alina [70]

Money makes for nice decimal examples.

If you had $1.50, and you wanted to split it among three people, you would have :

1.50 divided by 3 (which would be $0.50 each)

5 0

3 years ago

What’s the answer to (9n^2+3n+4) - (6n^2+3n+3)=

Brut [27]

The answer is 3n^2+1
9n^2 - 6n^2 = 3n^2
3n-3n=0
4-3=1

8 0

3 years ago

1. Alice invests $1000 at 2% interest compounded monthly over a 5 year period. Assuming no other money is deposited or withdrawn

eduard

Answer:

$1,105.08.

Step-by-step explanation:

Given that Alice invests $ 1000 at 2% interest compounded monthly over a 5 year period, assuming no other money is deposited or withdrawn, to determine what is the total amount of money in her account after 5 years, the following calculation must be performed:

X = 1,000 (1 + 0.02 / 12) ^ 5x12

X = 1,105.08

Thus, the amount of money in her account after 5 years would be $ 1,105.08.

6 0

3 years ago

The guitar that you always wanted is on sale in the music store. It costs 2/3 the original price. The guitar now costs $1996.67,

AysviL [449]

Answer:

3,327.9

Step-by-step explanation:

now: 1996.67

original: 3,327.9

1996.67/.6 = 3,327.9

4 0

4 years ago

For which function is f(x) equal to f^1(x) ( answer choices in picture )

Sonja [21]

Answer:

C. $f(x)=\frac{x+1}{x-1}$

Step-by-step explanation:

Let's find the inverse of each of the given options.

Option A:

$f(x)=\frac{x+6}{x-6}\\y=\frac{x+6}{x-6}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+6}{y-6}$

Rewrite in terms of 'y'. This gives,

$x(y-6)=y+6\\xy-6x=y+6\\xy-y=6x+6\\y=\frac{6x+6}{x-1}$

The given function $y=\frac{6x+6}{x-1}\ne y=\frac{x+6}{x-6}$

So, option A is incorrect.

Option B:

$f(x)=\frac{x+2}{x-2}\\y=\frac{x+2}{x-2}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+2}{y-2}$

Rewrite in terms of 'y'. This gives,

$x(y-2)=y+2\\xy-2x=y+2\\xy-y=2x+2\\y=\frac{2x+2}{x-1}$

The given function $y=\frac{2x+2}{x-1}\ne y=\frac{x+2}{x-2}$

So, option B is incorrect.

Option C:

$f(x)=\frac{x+1}{x-1}\\y=\frac{x+1}{x-1}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+1}{y-1}$

Rewrite in terms of 'y'. This gives,

$x(y-1)=y+1\\xy-x=y+1\\xy-y=x+1\\y=\frac{x+1}{x-1}$

The given function $y=\frac{x+1}{x-1}\ equals\ y=\frac{x+1}{x-1}$

So, option C is correct.

Option D:

$f(x)=\frac{x+5}{x-5}\\y=\frac{x+5}{x-5}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+5}{y-5}$

Rewrite in terms of 'y'. This gives,

$x(y-5)=y+5\\xy-5x=y+5\\xy-y=5x+5\\y=\frac{5x+5}{x-1}$

The given function $y=\frac{5x+5}{x-1}\ne y=\frac{x+6}{x-6}$

So, option D is incorrect.

Therefore, only option C is correct.

7 0

3 years ago