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Nookie1986 [14]
3 years ago
6

Determine the point estimate of the population proportion and the margin of error for the following confidence interval.Lower bo

undequals0.212​,upper boundequals0.758​,nequals1200The point estimate of the population proportion is . 485.​(Round to the nearest thousandth as​ needed.)The margin of error is 0.273.​(Round to the nearest thousandth as​ needed.)
Mathematics
1 answer:
Kamila [148]3 years ago
5 0

Answer: The point estimate of the population proportion is . 485.​

The margin of error is 0.273.​

Step-by-step explanation:

Confidence interval for population proportion(p):

sample proportion ± Margin of error

Given:  Lower bound of confidence interval  = 0.212

Upper bound = 0.758

⇒sample proportion - Margin of error=0.212  (i)

sample proportion + Margin of error= 0.758  (ii)

Adding (i) and (ii) , we get

2(sample proportion) =0.970

⇒ sample proportion = 0.970÷2= 0.485

Since sample proportion is the point estimate of the population proportion.

So, the point estimate of the population proportion=  0.485

Now put sample proportion =0.485 in (ii), we get

0.485+ Margin of error= 0.758

⇒  Margin of error= 0.758 - 0.485 =0.273

i.e. The margin of error is 0.273.​

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It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.

Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is

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<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>)   ==>   cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)

so that

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3 0
3 years ago
<img src="https://tex.z-dn.net/?f=18%20310%20%E2%88%92%209%20910%20%3D" id="TexFormula1" title="18 310 &minus; 9 910 =" alt="18
Marta_Voda [28]

Answer:

8400

Step-by-step explanation:

18310 - 9910

= 8400

Hope it helps you!!

#IndianMurga(. ❛ ᴗ ❛.)

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