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ZanzabumX [31]
3 years ago
13

Can a shape have an irrational area?

Mathematics
1 answer:
arlik [135]3 years ago
7 0
Yes of course because a shape is not nothing
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Find the solution to the following system of linear equations by using
Makovka662 [10]

Answer:

{x,y}={  

3

13

​  

,  

3

1

​  

}

Step-by-step explanation:

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System of Linear Equations entered :

  [1]    x + 2y = 5

  [2]    x - y = 4

Graphic Representation of the Equations :

   2y + x = 5        y + x = 4  

 

 

Solve by Substitution :

// Solve equation [2] for the variable  x  

 

 [2]    x = y + 4

// Plug this in for variable  x  in equation [1]

  [1]    (y +4) + 2y = 5

  [1]    3y = 1

// Solve equation [1] for the variable  y  

  [1]    3y = 1  

  [1]    y = 1/3  

// By now we know this much :

   x = y+4

   y = 1/3

// Use the  y  value to solve for  x  

   x = (1/3)+4 = 13/3  

Solution :

{x,y} = {13/3,1/3}

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How do you solve: cos(x-π/3)=-1​
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Answer:

x = \frac{4\pi }{3}

Step-by-step explanation:

given

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x - \frac{\pi }{3} = cos^{-1}(- 1) = π

Add \frac{\pi }{3} to both sides, hence

x = π + \frac{\pi }{3} = \frac{4\pi }{3}

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3 years ago
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