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yulyashka [42]
3 years ago
13

PLEASE HELP WITH THIS QUESTION

Mathematics
1 answer:
Burka [1]3 years ago
5 0
One nice thing about this situation is that you’ve been given everything in the same base. To review a little on the laws of exponents, when you have two exponents with the same base being:

– Multiplied: Add their exponents
– Divided: Subtract their exponents

We can see that in both the numerator and denominator we have exponents *multiplied* together, and the product in the numerator is being *divided* by the product in the detonator, so that translates to *summing the exponents on the top and bottom and then finding their difference*. Let’s throw away the twos for a moment and just focus on the exponents. We have

[11/2 + (-7) + (-5)] - [3 + 1/2 + (-10)]

For convenience’s sake, I’m going to turn 11/2 into the mixed number 5 1/2. Summing the terms in the first brackets gives us

5 1/2 + (-7) + (-5) = - 1 1/2 + (-5) = -6 1/2

And summing the terms in the second:

3 + 1/2 + (-10) = 3 1/2 + (-10) = -6 1/2

Putting those both into our first question gives us -6 1/2 - (-6 1/2), which is 0, since any number minus itself gives us 0.

Now we can bring the 2 back into the mix. The 0 we found is the exponent the 2 is being raised to, so our answer is

2^0, which is just 1.
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3 years ago
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A sample of size 45 will be drawn from a population with mean 53 and standard deviation 11. Use the TI-84 Plus calculator. (a) I
sukhopar [10]

Answer:

a) We have the standard deviation and the mean, so it is appropriate to use the normal distribution to find probabilities for x.

b) There is a 15.97% probability that x will be between 54 and 55.

c) The 47th percentile of x is X = 52.877.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

A sample of size 45 will be drawn from a population with mean 53 and standard deviation 11.

This means that \mu = 53.

We have to find the standard deviation of the sample, that is:

\sigma = \frac{11}{\sqrt{45}} = 1.64

(a) Is it appropriate to use the normal distribution to find probabilities for x?

We have the standard deviation and the mean, so it is appropriate to use the normal distribution to find probabilities for x.

(b) Find the probability that x will be between 54 and 55.

This is the pvalue of the Z score when X = 55 subtracted by the pvalue of the Z score when X = 54.

X = 55

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 53}{1.64}

Z = 1.22

Z = 1.22 has a pvalue of 0.88877.

X = 54

Z = \frac{X - \mu}{\sigma}

Z = \frac{54 - 53}{1.64}

Z = 0.61

Z = 0.61 has a pvalue of 0.72907.

So, there is a 0.88877 - 0.72907 = 0.1597 = 15.97% probability that x will be between 54 and 55.

(c) Find the 47th percentile of x. Round the answer to at least two decimal places.

This is the value of X when Z has a pvalue of 0.47;

This is between Z = -0.07 and Z = -0.08. So we use Z = -0.075.

Z = \frac{X - \mu}{\sigma}

-0.075 = \frac{X - 53}{1.64}

X = 52.877

The 47th percentile of x is X = 52.877.

8 0
3 years ago
Someone please help me in math
Helga [31]
I just solved it and I'm pretty sure its only one solution, I took the bottom equation multiplied it by -3 then i canceled out the equations and got 9. So that would make it C.
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\huge \boxed{\mathbb{QUESTION} \downarrow}

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\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

To solve these type of problems you need to use the pythagoras theorem ⇨ Hypotenuse² = Base² + Altitude².

Here,

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Now, let's solve for x.

Hypotenuse² = Base² + Altitude²

x² = (1.2)² + (1.6)²

x² = 1.44 + 2.56

x² = 4

x = √4

x = <em><u>2</u></em><em><u>.</u></em>

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<h3><u>NOTE</u><u> </u><u>:</u><u>-</u></h3>
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Answer:

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Step-by-step explanation:

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