Answer:
well i would just use my stand power to answer this but nahhh you got it g
Step-by-step explanation:
Step-by-step explanation:
When x = 0,
sin3x / 6x = 0 / 0, which is an indeterminate form.
Hence we use L'Hospital's rule:
d/dx (sin3x) = 3cos3x
d/dx (6x) = 6
Now we have 3cos3x / 6 or 0.5cos3x.
When x = 0, 0.5cos3x = 0.5(1) = 0.5.
Hence the limit is 0.5.
I got X = 6
If you replace x for 6 you should get 216
6^3 = 216
<span>6x^2 - 21x = 3x(2x - 7)
hope it helps</span>
