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ira [324]
3 years ago
15

What is 8 divided by 784

Mathematics
2 answers:
vlada-n [284]3 years ago
8 0

Answer:

8 divided by 784 is 0.01020408163

Step-by-step explanation:

Ilia_Sergeevich [38]3 years ago
3 0

Answer:

98

Step-by-step explanation:

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Help with this (explain in detail with the following vocab)
barxatty [35]

Answer Standard form

Step-by-step explanation:

5 0
4 years ago
Find the next two terms 1/8, 2/7,1/2,4/5
Verizon [17]

Answer:  5/4 and 6/3

Step-by-step explanation:

1/2 can be written as 3/6 so the series now becomes,

1/8 , 2/7 , 3/6 , 4/5 ,…….

i think you can now guess the answer, look at the<u> numerators which are increasing by ‘1’ </u>and then look at the <u>denominators which are decreasing by ‘1’.</u>

so the next number in the series is, 1/8 , 2/7 , 3/6 , 4/5 , 5/4 , 6/3

hope this helped

5 0
3 years ago
Set up an integral for the volume of the solid obtained by rotating the region bounded by the given curves about the specified l
Sloan [31]

Answer:

The integral of the volume is:

V = 32\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy

The result is: V = 78.97731

Step-by-step explanation:

Given

Curve: x^2 + 4y^2 = 4

About line x = 2 --- Missing information

Required

Set up an integral for the volume

x^2 + 4y^2 = 4

Make x^2 the subject

x^2 = 4 - 4y^2

Square both sides

x = \sqrt{(4 - 4y^2)

Factor out 4

x = \sqrt{4(1 - y^2)

Split

x = \sqrt{4} * \sqrt{(1 - y^2)

x = \±2 * \sqrt{(1 - y^2)

x = \±2 \sqrt{(1 - y^2)

Split

x_1 = -2 \sqrt{(1 - y^2)}\ and\ x_2 = 2 \sqrt{(1 - y^2)}

Rotate about x = 2 implies that:

r = 2 - x

So:

r_1 = 2 - (-2 \sqrt{(1 - y^2)})

r_1 = 2 +2 \sqrt{(1 - y^2)}

r_2 = 2 - 2 \sqrt{(1 - y^2)}

Using washer method along the y-axis i.e. integral from 0 to 1.

We have:

V = 2\pi\int\limits^1_0 {(r_1^2 - r_2^2)} \, dy

Substitute values for r1 and r2

V = 2\pi\int\limits^1_0 {(( 2 +2 \sqrt{(1 - y^2)})^2 - ( 2 -2 \sqrt{(1 - y^2)})^2)} \, dy

Evaluate the squares

V = 2\pi\int\limits^1_0 {(4 +8 \sqrt{(1 - y^2)} + 4(1 - y^2)) - (4 -8 \sqrt{(1 - y^2)} + 4(1 - y^2))} \, dy

Remove brackets and collect like terms

V = 2\pi\int\limits^1_0 {4 - 4 + 8\sqrt{(1 - y^2)} +8 \sqrt{(1 - y^2)}+ 4(1 - y^2)  - 4(1 - y^2)} \, dy

V = 2\pi\int\limits^1_0 { 16\sqrt{(1 - y^2)} \, dy

Rewrite as:

V = 16* 2\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy

V = 32\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy

Using the calculator:

\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy = \frac{\pi}{4}

So:

V = 32\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy

V = 32\pi * \frac{\pi}{4}

V =\frac{32\pi^2}{4}

V =8\pi^2

Take:

\pi = 3.142

V = 8* 3.142^2

V = 78.97731 --- approximated

3 0
3 years ago
What are the vertices of POR?
cupoosta [38]

Answer is (d) P, Q , R

Any triangle has 3 vertices , after which its name is justified

8 0
3 years ago
Is 3.4 a real number
anzhelika [568]

Answer: Yes, it is a real number. 3.4 is a rational number and rational numbers are real numbers. So 3.4 is a real number.

3 0
3 years ago
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