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user100 [1]
3 years ago
6

1)Solve G(x) for the given domain.

Mathematics
1 answer:
OverLord2011 [107]3 years ago
4 0

Answer:

anyone know the right answers

Step-by-step explanation:

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Can someone help me !
Aneli [31]

Answer:

  • with what <em>thigguyfgghiufguuyftuff6itry</em>
8 0
3 years ago
If (3a-5b) : (3a+5b)=1:4 then find the value of a:b​
rodikova [14]

Answer:

a : b = 25 : 9

Step-by-step explanation:

(3a - 5b) : (3a + 5b) = 1 : 4

Product of extremes = product  of  means

(3a - 5b) *4 = (3a +5b) * 1    {Distributive property}

3a * 4  - 5b*4 = 3a + 5b

12a - 20b = 3a + 5b

Add 20b to both sides

12a = 3a + 5b + 20b

12a = 3a + 25b

Subtract 3a from both sides

12a - 3a = 25b

9a = 25b

\dfrac{a}{b}=\dfrac{25}{9}

a:b = 25 : 9

5 0
3 years ago
The perimeter of a flag is 474 inches. The flag is 100 inches tall. How long is it?
zhannawk [14.2K]
The answer is 136 I hope this helped
3 0
3 years ago
Read 2 more answers
What is the solution of the equation over the complex numbers
denis-greek [22]

<u>Answer:</u>

2i\sqrt{3}

-2i\sqrt{3}

<u>Step-by-step explanation:</u>

x^2 + 12

First set the equation to 0

x^2 + 12

x^2 + 12 = 0

Second, get the 12 on the right side of the equal sign by adding a -12 to each side

x^2 + 12 = 0

x^2 + 12 + (-12) = 0 -12

x^2 = -12

Square root both sides of the equal sign.

x^2 = -12

\sqrt{x^2} = \sqrt{-12}

Take the square root on left sides of the equal sign.

\sqrt{x^2} = \sqrt{-12}

x = \sqrt{-12}

Take the square root on the right side of the equal sign. Remember \sqrt{-1} = i

x = \sqrt{-12}

x = \sqrt{4}*\sqrt{-1}\sqrt{3}}

x = 2i\sqrt{3}

<u>AND</u>

x = -2i\sqrt{3}

8 0
3 years ago
Can someone pls help me . Thank you .
Pavel [41]
Answer:
1). 24
2). 8

Explanation:
1).

285$ - 45$ = 240$
240$/10 = 24$

Therefore, he pays 24$ a month.

2).
Let x be the number than triple:

3x - 5 = 19
3x = 19 + 5
3x = 24
x = 24/3
x = 8
5 0
3 years ago
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