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Umnica [9.8K]
1 year ago
8

Find the domain of where f(x) = x + 10 and g(x)=x².

Mathematics
1 answer:
ASHA 777 [7]1 year ago
8 0

The domain of the function f(x)=x+10 is (-∞, ∞) and for the function g(x)=x² is (-∞, ∞).

<h3>What is meant by domain?</h3>

If a formula specifies a real function f, it may not be defined for some values of the variable. The natural domain or domain of definition of f is the set of real numbers on which the formula can be evaluated to a real number in this case. A partial function is often referred to just as a function, and its natural domain is referred to simply as its domain.

Given,  f(x) = x + 10

g(x)=x²

The domain for the function f(x)=x + 10

So, the domain of f(x)=x+10 is (-∞, ∞)

The domain for the function g(x)=x²

The expression's domain is only real numbers, with the exception of places where it is undefined. Because there is no real number in this scenario, the expression is undefined.

So, the domain of the function g(x)=x² is (-∞, ∞)

To know more about domain, visit:

brainly.com/question/28135761

#SPJ1

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4 years ago
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3. The diagonal of a rectangular field is 169 m. Ifthe ratio of the length to the width is 12:5, find the: (a) (b) dimensions; p
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The dimensions of the rectangle are length 156 m and a width of 65m, and a perimeter P = 442m

<h3>How to find the dimensions of the rectangle?</h3>

For a rectangle of length L and width W, the diagonal is:

D = \sqrt{L^2 + W^2}

Here we know that the diagonal is 169m.

And the ratio of the length to the width is 12:5

This means that:

W = (5/12)*L

Replacing all that in the diagonal equation:

169 = \sqrt{((5/12)^2*L^2 + L^2} \\\\169^2 = (25/144)*L^2 + L^2 = ( 25/144 + 1)*L^2\\\\\frac{169}{\sqrt{25/144 + 1} } = L = 156

So the length is 156 meters, and the width is:

W = (5/12)*156 m = 65m

Finally, the perimeter is:

P = 2*(L + W) = 2*(156 m + 65m) = 442m

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