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Rus_ich [418]
3 years ago
14

in c Write a program that reads an integer, a list of words, and a character. The integer signifies how many words are in the li

st. The output of the program is every word in the list that contains the character at least once. Assume at least one word in the list will contain the given character. Assume that the list will always contain less than 20 words. Each word will always contain less than 10 characters and no spaces.
Computers and Technology
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer:

see explaination

Explanation:

//Include required header file.

#include <stdio.h>

//Define the function isWordContainChar() having the

//required parameters.

int isWordContainChar(char* req_word, char search_char)

{

//Declare required variable.

int i;

//Start a for loop to traverse the string given in

//the function parameter.

for(i = 0; req_word[i] != '\0' ; i++)

{

//If the current character in the gievn word is

//matched with the character which needs to be

//found in the word, then return 1.

if(req_word[i] == search_char)

{

return 1;

}

}

//Otherwise, return 0.

return 0;

}

//Start the execution of the main() method.

int main(void)

{

//Declare the required variables.

int num_words, index, word_index;

char str_word[20][10];

char searchCharacter;

//Prompt the user to enter the number of words.

scanf("%d", &num_words);

//Prompt the user to enter the required words using a

//for loop and store them into an array.

for(index = 0; index < num_words; index++)

{

scanf("%s", str_word[index]);

}

//Prompt the user to enter a required character which

//needs to be found in a word.

scanf(" %c", &searchCharacter);

//Traverse the words stored in the array using a for

//loop.

for(index = 0; index < num_words; index++)

{

//Call the function isWordContainChar() with

//required arguments in rach iteration and if the

//value returned by this function is not 0, then

//display the current string in the array.

if(isWordContainChar(str_word[index],

searchCharacter) != 0)

{

printf("%s\n", str_word[index]);

}

}

return 0;

}

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Write a program that converts a number entered in Roman numerals to decimal. your program should consist of a class, say, Roman.
arlik [135]

Answer:

The code is given below in Java with appropriate comments

Explanation:

import java.util.*;

public class RomantoDecimal {

    public static void main(String[] args)

    {

         Scanner SC = new Scanner(System.in);

         RomantoDecimal r = new RomantoDecimal();

         System.out.println("Enter a Roman number :");

         // INPUT A ROMAN NUMBER

         String rNum = SC.next();

         // CALL convertToDecimal FOR CONVERSION OF ROMAN TO DECIMAL

         r.convertToDecimal(rNum);

    }

    // M=1000, D=500, C=100, L=50, X=10, V=5, I=1

    public void convertToDecimal(String roamNo)

    {

         int number = 0;

         // TEACK EACH DIGIT IN THE GIVEN NUMBER IN REVERSE ORDER

         for (int i = roamNo.length() - 1; i >= 0; i--)

         {

             // FIND OUT WHETHER IT IS 'M' OR NOT

             if (roamNo.charAt(i) == 'M')

             {

                  if (i != 0)

                  { // CHECK WHETHER THERE IS C BEFORE M

                       if (roamNo.charAt(i - 1) == 'C')

                       {

                            number = number + 900;

                            i--;

                            continue;

                       }

                  }

                  number = number + 1000;

             }

             // FIND OUT WHETHER IT IS 'D' OR NOT

             else if (roamNo.charAt(i) == 'D')

             {

                  if (i != 0)

                  {

                  // CHECK WHETHER THERE IS C BEFORE D

                       if (roamNo.charAt(i - 1) == 'C')

                       {

                            number = number + 400;

                            i--;

                            continue;

                       }

                 }

                  number = number + 500;

             }

            // FIND OUT WHETHER IT IS 'C' OR NOT

             else if (roamNo.charAt(i) == 'C')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i - 1) == 'X')

                       {

                            number = number + 90;

                            i--;

                            continue;

                      }

                  }

                  number = number + 100;

             }

             else if (roamNo.charAt(i) == 'L')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i) == 'X')

                       {

                            number = number + 40;

                            i--;

                            continue;

                       }

                  }

                  number = number + 50;

             }

             // FIND OUT WHETHER IT IS 'X' OR NOT

             else if (roamNo.charAt(i) == 'X')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i - 1) == 'I')

                       {

                            number = number + 9;

                            i--;

                            continue;

                       }

                  }

                  number = number + 10;

             }

             // FIND OUT WHETHER IT IS 'V' OR NOT

             else if (roamNo.charAt(i) == 'V')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i - 1) == 'I')

                       {

                            number = number + 4;

                            i--;

                            continue;

                       }

                  }

                  number = number + 5;

             }

            else // FIND OUT WHETHER IT IS 'I' OR NOT

             {

                  number = number + 1;

             }

         }// end for loop

         System.out.println("Roman number: " + roamNo + "\nIts Decimal Equivalent: " + number);

    }

}

3 0
3 years ago
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