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3 years ago

Simplify square root of negative 48

1 answer:

5 0

$\bf \sqrt{-48}\qquad 
\begin{cases}
48=2\cdot 2\cdot 2\cdot 2\cdot 3\\
\qquad 2^2\cdot 2^2\cdot 3\\
\qquad (2^2)^2\cdot 3
\end{cases}\implies \sqrt{-1\cdot (2^2)^2\cdot 3}
\\\\\\
\sqrt{-1}\cdot \sqrt{(2^2)^2\cdot 3}\implies i\cdot 2^2\sqrt{3}\implies 4\sqrt{3}\ i$

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−(−49) = −49 true or false?

vova2212 [387]

I hope this helps you

false

cause two negative numbers multiple must be positive

(-1).(-49)

+49

5 0

3 years ago

Pls help tap picture to see the three problems

valentinak56 [21]

1. Slope intercept form. First find two points to get slope: (0,-3) and (-3,-4). Slope is
(-4 - -3)/(-3 - 0)= 1/3
Use one of the points of (x,y) to solve for b
Y=1/3x + b
-3 = 1/3(0) + b
-3 = b so your slope intercept equation is
Y = 1/3x - 3

2. Rate of Change is slope. Your points are (0,10) and (24,6) so slope is (6-10)/(24-0)
= - 1/6 which means that for each 1 unit increase in x, y decreases by 1/6.

3. Standard form is ax + by =c
Notice it is the same line as in the first graph so it's the same equation
y = 1/3x - 3
First, you cannot have fractions, so you have to multiply the equation by 3 to get rid of the 1/3.
3y= x - 9. Now move the x over:
-x + 3y = - 9. Now get rid of the negative value on x by multiplying the entire equation by -1:
x - 3y = 9

8 0

3 years ago

A dilation with a scale factor of 2 is applied to the three line segments shown. The resulting images are P′Q′¯¯¯¯¯¯¯, A′B′¯¯¯¯¯

ivanzaharov [21]

Answer:

Step-by-step explanation:

Formula to determine the scale factor,

Scale factor = $\frac{\text{Dimension of the image}}{\text{Dimension of the original}}$

2 = $\frac{P'Q'}{PQ}$

2 = $\frac{P'Q'}{2}$

P'Q' = 4 cm

Similarly, for the length of A'B',

2 = $\frac{A'B'}{AB}$

2 = $\frac{A'B'}{1.5}$

A'B' = 3 cm

For the length of M'N',

2 = $\frac{M'N'}{MN}$

2 = $\frac{M'N'}{3}$

M'N' = 6 cm

4 0

3 years ago

The batteries from a certain manufacturer have a mean lifetime of 850 hours, with a standard deviation of 70 hours, assuming tha

matrenka [14]

To answer (a), we will need to find the Z value for 710 hours and 990 hours.

$\begin{gathered} For\text{ 710} \\ Z\text{ = }\frac{x-\mu}{\sigma} \\ \text{ = }\frac{710-850}{70} \\ \text{ = -2} \\ p\text{ =0.0228 } \\ For\text{ 990:} \\ Z\text{ = }\frac{990-850}{70} \\ \text{ =2} \\ p\text{ = 0.9772} \end{gathered}$ $\begin{gathered} To\text{ find P \lparen–2 \le Z \le 2\rparen} \\ =\text{ 0.9772 -0.0228} \\ =\text{ 0.9544} \\ =95.44\% \end{gathered}$

B) 68% of data lies between one standard deviation of the mean.

850 +70 = 920

850 - 70 = 780

5 0

1 year ago

Can someone help me? <br>

german

Step-by-step explanation:

p1=7

p2=10

p3=13

nxjdkkdkdkd

3 0

3 years ago