The slope would be 0 and it is a straight line line
Points equidistant from DE EF are in the bisector of angle DEF
points equidistant from EF DF are in the bisector of angle EFD
the sought after point is the intersection of bisectricess of triangle
2.5 * 3.5 = 8.75 or 8 3/4 inches long
Answer: (A) 19.3%
<u>Step-by-step explanation:</u>
Vodka + Vermouth + Olive = Total Cost
$2.59 + $0.12 + $0.15 = $2.86
Answer:
Step-by-step explanation:
A circle centered at (0,0) with radius r is
Since your circle has diameter of 12, then its radius is 6. Then
So a possible answer is:
If you want to move the location of the center, but keep it on the x-axis, then add or subtract a number to the x, such as this:
The center of this circle would be (-4, 0) which is still on the x-axis.