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Katyanochek1 [597]
3 years ago
12

Find the angle measurements and side lengths for the triangle below

Mathematics
1 answer:
rewona [7]3 years ago
4 0

Answer:

Step-by-step explanation:

Sin(A) = 5/7

Sin(A) = 0.7143

A = sin-1(0.7143

A = 45.58

B = 180 - 45.58 - 90

B =  44.43

C = 90

c = 7

a = 5

b^2 = c^2 - a^2

b^2 = 7^2 - 5^2

b^2 = 49 - 25

b^2 = 24

b = 4.899

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MAXImum [283]

Answer:

Step-by-step explanation:

a) The domain is R- all real numbers.

b) The domain is R- all real numbers.

c) we need

x^{2}-4\neq  0\\x^{2} \neq 4\\x\neq 2\\and\\x\neq -2

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d)

we need

x^{2}+x-2\neq  0\\x\neq 1\\and\\x\neq -2

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e)

we need: x-1>0 or x> 1

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6 0
3 years ago
I NEED HELP ASAP 6th GRD WORK HELPPP
tatuchka [14]

Answer:

28cm

Step-by-step explanation:

A=a+b

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3 years ago
Solve by completing the square​
erastovalidia [21]

Answer:

Your answers would be:

x = 10 and x = -8

Step-by-step explanation:

Solve for the zeros:

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x² - 2x - 80 = 0

Use the quadratic formula: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a = 1

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c = -80

Plug in and solve:

x=\frac{-(-2)\pm\sqrt{(-2)^2-4(1)(-80)}}{2(1)}\\\\x=\frac{2\pm\sqrt{(-2)^2-4(1)(-80)}}{2(1)}\\\\x=\frac{2\pm\sqrt{4-4(-80)}}{2(1)}\\\\x=\frac{2\pm\sqrt{4+320}}{2(1)}\\\\x=\frac{2\pm\sqrt{324}}{2(1)}\\\\x=\frac{2\pm18}{2}\\

Solve for +:

x=\frac{2+18}{2}\\\\x=\frac{20}{2}\\\\x=10

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5 0
3 years ago
a ramp measures 6 feet long. if the ramp is 12 inches tall, what is the horizontal distance that it covers?
svp [43]
We know that

1 ft--------> is equals to 12 in
the ramp is 12 inches tall----------> 1 ft tall
<span>A ramp measures------------------>  6 ft long
</span>
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</span>c²=a²+b²
where
c-----> 6 ft long
a----> horizontal distance
b-----> 1 ft tall

a²=c²-b²------> a²=6²-1²-----> a²=35------> a=√35------> a=5.92 ft

the answer is
5.92 ft

8 0
4 years ago
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Rashid [163]

Answer:

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So, 1V + 1V + 1V + 1V

= 4V

8 0
3 years ago
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