3(1+2)
3+6
9 ( the answer is nine)
first you divide six and two then use the distributive property to multiply three and one and three and two, then add three and six to get nine.
Answer:
no worries about the other day and I had literally forgotten about the other night and was just so I could tell me how I felt and I had a flat rate that you and I had a
Answer:
-11
Step-by-step explanation:
-3-(-2)+(-10)
Two - make a pos -3+2+(-10)
-1+(-10)
-11
Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
===============================================
Problem 2
<h3>Answer: True</h3>
---------------------------------
Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
Answer:
Step-by-step explanation:
Notice that function 
has the exat shape of function 
, and it has just be translated to the right by 3 whole units.
Recall that horizontal translations to the right involve subtracting the number of units moved in the translation from the variable "x". therefore, in our case this means:
