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natita [175]
3 years ago
12

Help please...no links...

Mathematics
1 answer:
Likurg_2 [28]3 years ago
3 0

the answer is 3/4 or c.

Step-by-step explanation:

to find tan A you would use the equation of tan which is the value opposite the angle A which is 27 over the value adjacent to the angle which is 36.

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Please answer I need it asap. Please solve if you can!
tensa zangetsu [6.8K]

Answer: y=-0.54x+19.8

Step-by-step explanation:

Because it is asking for a line, it cannot be the first option (which is a quadratic) or the fourth option (which is an exponential).

This leaves us with the second and third options.

Since the line will have a negative slope (as the data is decreasing), this means that the only viable option is y=-0.54x+19.8.

7 0
2 years ago
What is​ 3/5 ​written as a percent?<br><br> A 3.5%<br><br> B 30%<br><br> C 35%<br><br> D 60%
goldfiish [28.3K]
D is the correct answer.
6 0
3 years ago
Read 2 more answers
HELP ASAP WILL MARK BRAINLIEST AREA OF FIGURES
Lerok [7]

Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

1.

Cylinder:

V = \pi r^{2}h               *Plug in numbers*

(3.14)(2.5)^{2}(7)         *Square 2.5*

(3.14)(6.25)(7)        *Solve*

≈ 137.375in^{3}

Sphere:

V = \frac{4}{3}\pi r^{3}              *Plug in numbers*

\frac{4}{3} (3.14)(2.5)^{3}         *Cube 2.5*

\frac{\frac{4}{3}(3.14)(15.625)}{2}         *Divide by 2 and Solve*

≈ 32.7083 in^{3}

Add both volumes

137.375 + 32.7083 ≈ 170.083in^{3}

2.

Cylinder:

V = \pi r^{2}h         *Plug in numbers*

\pi (3)^{2}(10)            *Square 3*

\pi (9)(10)             *Multiply*

90\pi

Sphere:

V = \frac{4}{3} π r^{3}            *Plug in numbers*

\frac{4}{3}\pi (3)^{3}                   *Cube 3*

\frac{4}{3} \pi (27)                   *Multiply*

36\pi

Add both Volumes to get total

90\pi + 36\pi = 126in^{3}

3.

Sphere:

V = \frac{4}{3}\pi r^{3}              *Plug in numbers*

\frac{4}{3} (3.14)(3)^{3}            *Cube 3*

\frac{4}{3} (3.14)(27)            *Multiply*

113.04m^{3}

Cone:

V = \frac{\pi r^{2}h}{3}             *Plug in numbers*

\frac{(3.14)(2)^{2}(5)}{3}           *Square 2*

\frac{(3.14)(4)(5)}{3}             *Solve*

20.93m^{3}

Subtract the volumes to get the volume of the blue area

113.04 - 20.93 = 92.106m^{3}

4.

Sphere:

V = \frac{4}{3} \pi r^{3}            *Plug in numbers*

\frac{4}{3}\pi (8)^{3}                 *Cube 8*

\\\frac{4}{3}\pi (512)               *Multiply*

\\\\\pi (682.6)              *Solve*

2133.66in^{3}           *Divide by 2 since it's a hemisphere*

Cone:

V = \frac{\pi r^{2}h}{3}            *Plug in numbers*

\frac{\pi (8)^{2}(20)}{3}              *Square 8*

\frac{\pi (64)(20)}{3}              *Multiply and Divide*

1340.41 in^{3}

Add both volumes

1072.33 + 1340.41 = 2412.74in^{3}

5.

Cylinder:

V = \pi r^{2}h            *Plug in numbers*

\pi (6)^{2}(16)              *Square 6*

\pi (36)(16)             *Multiply*

576\pi

Cone:

V = \frac{\pi r^{2}h}{3}            *Plug in numbers*

\frac{\pi (6)^{2}3}{3}                  *Square 6*

36\pi

Add both volumes

576\pi + 36\pi = 612\pi m^{3}

Alternative: *Multiply π*

1922m^{3}

4 0
3 years ago
Read 2 more answers
Please help! 15 Points!
san4es73 [151]

Answer:

Option C and D

Step-by-step explanation:

2π/3 refers 120°which falls in the second quadrant. In second quadrant sin  value is positive and tan & cos value is negative.

tan 120 = - tan 60 = -√3

4 0
2 years ago
A manufacturing operations consists of 12 operations. However, five of the 12 machining operations must be completed before any
shutvik [7]

Answer:

604800 possibilities

Step-by-step explanation:

There are two sets.

The first set is for the first five machining operations. This set has the following operations: A,B,C,D,E

The first operation to be made can be any of them(A,B,C,D,E). The second will be any of the four remaining ones, the third will be any of the three remaining and so on...

So for the first set there are 5*4*3*2*1 = 5! = 120 possibilities.

Now for the second set, the same logic is applied.

There will be 7*6*5*4*3*2*1 = 7! = 5040 possibilities.

Now taking into account all the 12 operations, separated by set, there will be 120*5040 = 604800 possibilities.

You can understand this calculus as that for a simple possibility of the first set, there are 5040 possibilities of the second set. The are 120 possiblities in the first set, so we have the multiplication in the paragraph above.

4 0
3 years ago
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