What we know:
quotient 9.2 x 10^6/ 2.3 x 10²
in quotients exponents are subtracted of they have the same base, for example 10^6 and 10² have the same base of 10
What we need to find: quotient 9.2 x 10^6/ 2.3 x 10²
9.2 x 10^6
-------------- = 4 x 10^4
2.3 x 10²
Here in this problem I divided 9.2 by 2.3 and got 4, since the solution was simple and clean meaning no repeated decimals I went ahead and divided the 10^6 by 10^2 and got 10^4.
Another method would be to expand both numbers then divide and do scientific notation again.
Remember to change to normal notation you move the decimal to the right using the number of the exponent.
9.2 x 10^6= 9200000
2.3 x 10²= 230
920000/230=40000
40000= 4 x 10^4 scientific notation
Use the method that is best for you or just know you can use either method to check your work.
Answer:
No x-intercept/Zero
Step-by-step explanation:
..........,............
Answer: The second option (160 cm)
Step-by-step explanation:
1. You can obtain the perimeter of a quadrilateral by adding the lenghts of the sides.
2. You know that the ratio of the side lengths is 3:3:5:8 and the perimeter is 380 centimeters.
3. Therefore, you can write the following expression, where x is an integer:
4. Solve for x:
5. Therefore, the longest side is:
(160 cm)
The number=10x+y
we suggest this system of equations:
(10y+x)-(10x+y)=27
x+y=9 ⇒x=9-y
Can solve this system of equations by susbstitution method.
(10y+(9-y)-(10(9-y)+y)=27
10y+9-y-(90-10y+y)=27
10y-y+10y-y=27-9+90
18y=108
y=108/18
y=6
x=9-y
x=9-6
x=3
The number=10x+y=10(3)+6=36
Answer: the number is 36.
to check:
63-36=27
6+3=9
9514 1404 393
Answer:
-13/11
Step-by-step explanation:
Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...
![\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto%201%7D%5Cdfrac%7Bn%7D%7Bd%7D%3D%5Cdfrac%7Bn%27%7D%7Bd%27%7D%3D%5Cleft.%5Cdfrac%7B%5Cdfrac%7B4%7D%7B3%5Csqrt%5B3%5D%7B4x-3%7D%7D-%5Cdfrac%7B7%7D%7B2%5Csqrt%7B7x-6%7D%7D%7D%7B%5Cdfrac%7B5%7D%7B2%5Csqrt%7B5x-4%7D%7D-%5Cdfrac%7B2%7D%7B3%5Csqrt%5B3%5D%7B2x-1%7D%7D%7D%5Cright%7C_%7Bx%3D1%7D%3D%5Cdfrac%7B4%2F3-7%2F2%7D%7B5%2F2-2%2F3%7D%3D%5Cdfrac%7B8-21%7D%7B15-4%7D%5C%5C%5C%5C%3D%5Cboxed%7B-%5Cdfrac%7B13%7D%7B11%7D%7D)
