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natka813 [3]
3 years ago
9

Rafael is taking a test that contains a section of 12 true-false questions. how many of the possible groups of answers to these

questions have exactly 8 correct answers of false?
Mathematics
1 answer:
stiv31 [10]3 years ago
5 0
Answer: There are 495 possible different sets of answers the could contain exactly 8 correct answers of false.

Basically, we are looking for the number of different ways of selecting 8 objects out of a set of 12 objects. Our objects are answers of false and the set is the test.

This is a combination problem. The formula would be:

12! / (8! x 4!) = 495
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ABC is the middle line of MN in an equilateral triangle. If AB = 8 cm, then find the perimeter MBN.
qaws [65]

Answer:

the answer is 12

Step-by-step explanation:

since the triangle is equilateral meaning all side of ABC is equal to each other AB= BC = AC= 8cm and MN is the middle line that divides AB and BC by two

thus, MB =BN= 4 cm. MN is the middle line thus will also be equal to the half of AC  meaning MN=AC/2= 4cm. and perimeter  is MBN = MN+MB+BN= 4cm+4cm+4cm =12cm

4 0
3 years ago
If the sum of three consecutive odd integers is at most 216, what is the largest possible value of one of those integers?
galben [10]

Answer:

yes

Step-by-step explanation:

6 0
3 years ago
Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec
german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. \frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}} Therefore, because sin is y/r, r = \sqrt{5} and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = \frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = 4\sqrt{2}. Now, to find csc, we have to do r/y.

csc = \frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = \sqrt{7/16} = \frac{\sqrt{7}}{4}

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -\sqrt{7/9} = \frac{-\sqrt{7}}{3}

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = (\frac{-\sqrt{6}}{2})^{2}

1 + cot^2 = 6/4

cot^2 = 2/4

cot = \frac{\sqrt{2}}{2}

tan = \sqrt{2}

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

(\frac{2}{\sqrt{2}})^2 + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -\sqrt{3}

cos = \frac{-\sqrt{3}}{3}

Hope this helps!! :)

3 0
3 years ago
Read 2 more answers
How much does each one equal?​
nadya68 [22]

Answer:

need more information

4 0
3 years ago
Need help plz i dont know how to do this
nexus9112 [7]
You FOIL
9x^2-15x+21x-35
Combine like terms
9x^2 + 6x - 35
8 0
3 years ago
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