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Naddika [18.5K]
2 years ago
12

Can anybody tell me what is the answer to -2/5 - (-1/10)

Mathematics
1 answer:
liubo4ka [24]2 years ago
6 0

\frac{ - 3}{10}

Hope it helps

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The coordinates of an ordered pair have opposite signs. In which quadrant(s) must the ordered pair lie? Explain.
Alex_Xolod [135]
Alright...so the coordinates of an ordered pair have opposite signs [one sign is positive while the other is negative] so we could have an example of (-x,+y) or (+x,-y) ...that means out of the 4 quadrants these points could be in the 2nd quadrant or the 4th quadrant or corners of the graph

7 0
3 years ago
If a certain cannon is fired from a height of 8.8 meters above the​ ground, at a certain​ angle, the height of the cannonball ab
Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

h(t)=-4.9t^2+30.5t+8.8

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

-4.9t^2+30.5t+8.8=0

Multiply both sides by 10.

-49t^2+305t+88=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are: x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a = -49, b = 305 and c=88

t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}

Ignore the negative value of t as time can't be a negative number.

Thus,

t=\frac{305+\sqrt{110273}}{98}\approx6.50

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0
3 years ago
What is the area of the triangle? On a coordinate plane, a triangle has a base of 8 units and a height of 6 units. 24 square uni
LekaFEV [45]

Answer:

24

Step-by-step explanation:

8*6=48/2=24

6 0
3 years ago
Read 2 more answers
I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct
joja [24]
*If you need me to do #5, DM me!

3. 
The area of a triangle can be given by (just plug and chug as always):
A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2
A_r = bh = 12(8) = 96m^2
Now we just add them:
96+12 = 108m^2

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
A_t = \frac{1}{2}bh
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2
Multiply by 4 to get total area:
6.25*4 = 25cm^2

So, the area of the given rhombus is 25cm².
8 0
3 years ago
Hudson is performing an experiment by tossing a paper cup into the air and recording how it lands. He determines that there are
Debora [2.8K]
It has landed on its side 25/30 times, on the top 4/30 times 25/30=5/6,1/30=0.2/6 and 4/30=0.8/6.
3 0
4 years ago
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