do you need to include the wiggle infront of the first bracket? if not;
(x+1) ÷ [(x^2+2) x (2x-3dx)]
x^2 x 2x = 2x^3
x^2 x -3dx = -3dx^3
2 x 2x = 4x
2 x -3dx = - 6dx
i cant find a way to make it equal 0 so i think the answer is just
x+1 over 2x^3 - 3dx^3 + 4x - 6dx as a fraction
Answer:
In the picture above.
Step-by-step explanation:
I hope that it's a clear solution.
Good luck:)
326=12m+6c+x The reason your x does not have a number is because it is unknown so in order to solve for x you need to get rid of the 12m+6c so in order to that you can divide it on both sides so you would get 326/12m+6c=x the divide your numbers 18.1=x but you cant have a tenth of a djembe drum so you would have to round up to 19.
Answer:
c=pi x d
3.14x12.5
d is the answer
Step-by-step explanation:
