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gregori [183]
3 years ago
10

A projectile is launched upward with a velocity of 256 feet per second from the top of a 35-foot structure. What is the maximum

height attained by the projectile?

Mathematics
1 answer:
zhuklara [117]3 years ago
3 0

Answer:

  1059 ft

Step-by-step explanation:

For problems like these, we assume the acceleration due to gravity is -32 ft/s², so the velocity will decrease to zero in time t, where ...

  0 = 256 -32t

  32t = 256

  t = (256 ft/s)/(32 ft/s² ) = 8 s

Since velocity is linearly decreasing from 256 ft/s to 0, its average value of 128 ft/s will serve to tell us the height attained.

Height attained is ...

  35 ft + (128 ft/s)(8 s) = 35 ft + 1024 ft = 1059 ft

The maximum height attained by the projectile is 1059 feet.

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Help me please I’m begging you:(
alex41 [277]

Answer:

Chips = 14

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Step-by-step explanation:

First Equation:

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6 0
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Step-by-Step explanation:

Common knowledge: Anytime you have the same numerator, with a different denominator, the one with the bigger denominator is always smaller. For example, if had a pizza with 6 slices and a pizza with 4 slices, the one with 6 slices and smaller and the one with 4 slices and bigger. Even though 6>4 that mindset has to change when thinking about a problem like this.

<em>Another explanation: </em>

<em>If you still don’t get it, simply find a common denominator, so we’ll choose 12. Take 3/6 and multiply that by 2/2 so you get 6/12 and then take 3/4 and multiply that by 3/3 on both the (numerator and denominator) and that equals 9/12.</em>

<em>So now you have the expression: 6/12<9/12.</em>

7 0
3 years ago
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