A projectile is launched upward with a velocity of 256 feet per second from the top of a 35-foot structure. What is the maximum
height attained by the projectile?
1 answer:
Answer:
1059 ft
Step-by-step explanation:
For problems like these, we assume the acceleration due to gravity is -32 ft/s², so the velocity will decrease to zero in time t, where ...
0 = 256 -32t
32t = 256
t = (256 ft/s)/(32 ft/s² ) = 8 s
Since velocity is linearly decreasing from 256 ft/s to 0, its average value of 128 ft/s will serve to tell us the height attained.
Height attained is ...
35 ft + (128 ft/s)(8 s) = 35 ft + 1024 ft = 1059 ft
The maximum height attained by the projectile is 1059 feet.
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