Answer:
![\triangle PQR \sim \triangle TSR](https://tex.z-dn.net/?f=%5Ctriangle%20PQR%20%5Csim%20%5Ctriangle%20TSR)
Step-by-step explanation:
Given :
QR⊥PT
![\angle QPR = \angle STR](https://tex.z-dn.net/?f=%5Cangle%20QPR%20%3D%20%5Cangle%20STR)
To Prove : ![\triangle PQR \sim \triangle TSR](https://tex.z-dn.net/?f=%5Ctriangle%20PQR%20%5Csim%20%5Ctriangle%20TSR)
Solution:
Statements Reasons
QR⊥PT Given
∠QRP and ∠SRT are right angles Def of perpendicular
∠QPR≅∠STR Given
∠QRP = ∠SRT All right angles are equal
ΔPQR≈ΔTSR AA similarity
Hence ![\triangle PQR \sim \triangle TSR](https://tex.z-dn.net/?f=%5Ctriangle%20PQR%20%5Csim%20%5Ctriangle%20TSR)
3% = .03
200 × .03 = 6
6 × 2 = 12
Answer: D
Answer:
0.0000123
Step-by-step explanation:
That " -5 " exponent requires that we move the decimal place 5 units to the left, which results in:
0.0000123
Answer:
it is 750 ml of flour this is the answer