The 2 equations are
-2x + y = -17 ---1)
3x + y = 23 ---2)
we need to have the same coefficient for one of the variables.
Already y variable has the coefficient of 1 for both equations so we can use the equations as it is.
2) - 1) subtract 1) from 2)
3x-(-2x) + y -y = 23-(-17)
5x = 40
x = 8
substituting x = 8 in the 2nd equation
3*8 + y = 23
24 + y = 23
y = -1
solution - (8,-1)
The answer is log3 k to the seventh power m to the sixth power over n to the ninth power
a * logₓ(y) = logₓ(yᵃ)
7 log₃ (k) = log₃ (k⁷)
6 log₃ (m) = log₃ (m⁶)
9 log₃ (n) = log₃ (n⁹)
7 log₃ (k) + 6 log₃ (m) - 9 log₃ (n) = log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹)
logₓ(y) + logₓ(z) = logₓ(y * z)
log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶) - log₃ (n⁹)
logₓ(y) - logₓ(z) = logₓ(y / z)
log₃ (k⁷ * m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶ / n⁹)
Answer:
15/40 or simplified 3/8
Step-by-step explanation:
I think the answer is 11 3
Answer: imma say A
Step-by-step explanation: sorry if wrong
