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2 years ago

What is the solution to the equation fraction 1 over 4x = 5?

Mathematics

1 answer:

Amanda [17]2 years ago

6 0

C) x=20
$x = 20$

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4.7

Step-by-step explanation:

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2 years ago

It is claimed that an automobile is driven on the average more than 20,000 kilometers per year. To this claim, a random sample o

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Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Sample mean(x) = 23500

Sample standard deviation (sd) = 3900

Sample size (n) = 20

Population mean (m) = 20,000

Null hypothesis : m = 20000

H1: m > 20000

To obtain the z-score :

(population mean - sample mean) / (sample standard deviation /√sample size)

(x - m) / (sd/√n)

(23500 - 20000) / (3900 / √20)

3500 / (3900 /4.4721359)

3500 / 872.06651

= 4.0134

Get the P value to know if to reject or accept the null:

P(z > 4.0134) = 1 - P(z < 4.0134)

P(z < 4.0134) = 1

1 - P(z < 4.0134) = 1 - 1 =0

Since P value is < alpha, we reject the null.

Hence average is > 20000

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2 years ago

Paul's bathtub is clogged. He has to empty 30 liters of water by hand. Paul has a 3- liter, a 4- liter, and a 5 liter bucket. Of

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3 and 4 + 3 and 4 + 3 and 4 + 4 and 5 = 30

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2 years ago

Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni

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Answer:

The required equation $k-2=\dfrac{1}{9}(t-18)$

C should be correct.

Step-by-step explanation:

Given: Julissa is running a 10-kilometer race at a constant pace.

After running for 18 minutes, she completes 2 kilometers.

First point: (18,2)

After running for 54 minutes, she completes 6 kilometers.

Second Point: (54,6)

We need to write an equation letting t, the time in minutes, represent the independent variable and k, the number of kilometers, represent the dependent variable

Using two point formula to find the equation of line

Formula:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

Required Equation:

$k-2=\dfrac{6-2}{54-18}(t-18)$

$k-2=\dfrac{4}{36}(t-18)$

$k-2=\dfrac{1}{9}(t-18)$

Hence, The required equation $k-2=\dfrac{1}{9}(t-18)$

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