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STatiana [176]
3 years ago
6

Congruence transformation pls help im despo

Mathematics
2 answers:
Tomtit [17]3 years ago
7 0

Answer:

X,2,3

Step-by-step explanation:

LEARN THIS PLZ

Alex Ar [27]3 years ago
4 0

Answer:

Step-by-step explanation:

Reflect over Ox axis , then translate x+6 , y-1

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One store has carrots on sale for $1.1 for 3 pounds, while another store has carrots on sale for $0.78 for two pounds. Which sto
irina1246 [14]

Answer:

1) The store selling for 1.1 per 3 lbs

2) $6.24

Step-by-step explanation:

1)

1.1/3 = 0.37

0.78/2 = 0.39

0.37 is cheaper so it's a better deal

2)

\frac{0.78}{3} =\frac{x}{24} \\\\3x=18.72\\x=6.24

4 0
3 years ago
Read 2 more answers
A. 115<br> B. 167<br> C. 126<br> D. 96
geniusboy [140]

Answer:

126

Step-by-step explanation:

Let x be the missing length

The triangles are similar:

● UE/140 = 45/x

From the graph we deduce that:

● UE = 140 - 90 = 50

Replace UE by its value

● 50/ 140 = 45/x

Switch x and 50

● x / 140 = 45/50

45/50 is 9/10 wich is 0.9

● x/140 = 0.9

Multiply 0.9 by 140

● x = 140 × 0.9

● x = 126

5 0
3 years ago
Read 2 more answers
Helpppppp$$$!!!!!!!!!!!!!!!!! Plz
insens350 [35]

9514 1404 393

Answer:

  B

Step-by-step explanation:

Given the triangle congruence statements, the segment and angle congruence statements must refer to corresponding vertices. Corresponding vertices are listed in the same order in the triangle congruence statement.

The one FALSE statement in the bunch is ...

  \overline{OD}\cong\overline{AL}

__

The true statements for these segments would be ...

  \overline{OD}\cong\overline{JL}\\\\\overline{CD}\cong\overline{AL}

5 0
3 years ago
Lots of points <br><br>Please help<br><br>i add a photo ​
valkas [14]
C = 6*P

Use that formula and plug in the x-axis values for P and plot the results (C) on the graph
3 0
2 years ago
Read 2 more answers
The 12th term of a sequence is 41 and the 15th term is 140. What is the nth term?
OLga [1]
An= mth term.
an=a₁+(n-1)*d

a₁₂=41
a₁₅=140

a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d 
a₁+11d=41    (1)

a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d 
a₁+14d=140    (2)

With the equiations (1) and (2)  build a system of equations
a₁+11d=41
a₁+14d=140

we solve it.
-(a₁+11d=41)
  a₁+14d=140
--------------------
       3d=99  ⇒d=99/3=33

a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322

an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n

an=-355+33n

To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
3 0
3 years ago
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