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Scilla [17]
3 years ago
11

PLEASE HELP I GIVE THANKS

Mathematics
1 answer:
Dovator [93]3 years ago
8 0
It has 9 sides. Hope my answer was useful
You might be interested in
For which table would 70 be the missing value,x?
Mila [183]

data test;

input landval improval totval salepric saltoapr city $6. season $8.;

datalines;

  30000     64831     94831    118500   1.25  A    spring

  30000     50765     80765     93900    .         winter

  46651     18573     65224         .   1.16  B      

  45990     91402         .    184000   1.34  C    winter

  42394         .     40575    168000   1.43        

      .      3351     51102    169000   1.12  D    winter

  63596      2182     65778         .   1.26  E    spring

  56658     53806     10464    255000   1.21      

  51428     72451         .         .   1.18  F    spring

  93200         .      4321    422000   1.04      

  76125     78172     54297    290000   1.14  G    winter

      .     61934     16294    237000   1.10  H    spring

  65376     34458         .    286500   1.43       winter

  42400         .     57446         .    .    K    

  40800     92606     33406    168000   1.26  S    

;

run;

1. Number of missing values vs. number of  non missing values in each variable

The first thing we are going to look at the variables that have a lot of missing values. For numerical variables, we use proc means with the options n and nmiss.

proc means data = test n nmiss;

 var _numeric_;

run;

Variable N N Miss

landval 13 2

improval 12 3

totval 12 3

salepric 11 4

saltoapr 13 2

For character variables, we can use proc freq to display the number of missing values in each variable.

proc freq data = test;

 tables city season ;

run;

 

city Frequency Percent Cumulative Cumulative

Frequency Percent

A 1 10 1 10

B 1 10 2 20

C 1 10 3 30

D 1 10 4 40

E 1 10 5 50

F 1 10 6 60

G 1 10 7 70

H 1 10 8 80

K 1 10 9 90

S 1 10 10 100

Frequency Missing = 5

season Frequency Percent Cumulative Cumulative

Frequency Percent

spring 4 44.44 4 44.44

winter 5 55.56 9 100

Frequency Missing = 6

2. Number of missing values in each observation

We can also look at the number of missing values in each observation. For example, we can use SAS function cmiss to store the number of missing values from both numeric and character variables in each observation.

data test1;

 set test;

 miss_n = cmiss(of landval -- season);

run;

proc print data = test1;  

run;

                                                                 

Obs landval improval totval salepric saltoapr city season miss_n

1 30000 64831 94831 118500 1.25 A spring 0

2 30000 50765 80765 93900 .  winter 2

3 46651 18573 65224 . 1.16 B  2

4 45990 91402 . 184000 1.34 C winter 1

5 42394 . 40575 168000 1.43   3

6 . 3351 51102 169000 1.12 D winter 1

7 63596 2182 65778 . 1.26 E spring 1

8 56658 53806 10464 255000 1.21   2

9 51428 72451 . . 1.18 F spring 2

10 93200 . 4321 422000 1.04   3

11 76125 78172 54297 290000 1.14 G winter 0

12 . 61934 16294 237000 1.1 H spring 1

13 65376 34458 . 286500 1.43  winter 2

14 42400 . 57446 . . K  4

15 40800 92606 33406 168000 1.26 S  1

3. Distribution of missing values

We can also look at the patterns of missing values. By default the MI procedure will output missing data patterns for the variables in the specified datasets. If no var statement is specified Proc MI will output a table for the all the variables in a dataset. The ods select statement tells SAS to only output the "Missing Data Patterns" table.

proc mi data=test;

ods select misspattern;

run;

Missing Data Patterns

Group landval improval totval salepric saltoapr Freq Percent Group Means

landval improval totval salepric saltoapr

1 X X X X X 4 26.67 50896 72354 48250 207875 1.215

2 X X X X . 1 6.67 30000 50765 80765 93900 .

3 X X X . X 2 13.33 55124 10378 65501 . 1.21

4 X X . X X 2 13.33 55683 62930 . 235250 1.385

5 X X . . X 1 6.67 51428 72451 . . 1.18

6 X . X X X 2 13.33 67797 . 22448 295000 1.235

7 X . X . . 1 6.67 42400 . 57446 . .

8 . X X X X 2 13.33 . 32643 33698 203000 1.11

You will notice that this report only contains information for numeric variables not character. Another approach to achieve the same output could be via making use of formats, which then allows for character variables to be included. The order of the patterns is different but the information is still the same.

proc format;

value nm . = '.' other = 'X';

value $ch ' ' = '.'other = 'X';

run;

proc freq data=test;

table landval*improval*totval*salepric*saltoapr*city*season / list missing nocum;

format _numeric_ nm. _character_ $ch.;

run;

landval improval totval salepric saltoapr city season Frequency Percent

. X X X X X X 2 13.33

X . X . . X . 1 6.67

X . X X X . . 2 13.33

X X . . X X X 1 6.67

X X . X X . X 1 6.67

X X . X X X X 1 6.67

X X X . X X . 1 6.67

X X X . X X X 1 6.67

X X X X . . X 1 6.67

X X X X X . . 1 6.67

X X X X X X . 1 6.67

X X X X X X X 2

8 0
3 years ago
Read 2 more answers
Can two positive integers have their H.C.F and L.C.M as 12 and 512 respectively? justify.
DaniilM [7]

Here is your answer

NO

Reason:

H.C.F. divides the L.C.M. completely.

Here 512 is not completely divided by 12

So, two numbers can't have their H.C.F and L.C.M as 12 and 512 respectively.

HOPE IT IS USEFUL

7 0
3 years ago
Read 2 more answers
In the Volume of Prisms section, where is the height of a prism located? *
quester [9]
C) Thé distance between the two bases



Explanation:

Hope that helps
7 0
4 years ago
Please help !!!!!!!!!!!!
Nataly [62]

Answer:

90 degrees

Step-by-step explanation:

3 0
3 years ago
To divide the sector into two congruent sectors we can use the _________________ construction. A) angle bisector B) copy and ang
12345 [234]

Answer:

Option A) angle bisector

Step-by-step explanation:

Angle Bisector:

  • An angle bisector is a line that divides an angle into two equal parts.
  • The angle bisector divide the angle in two equal parts.
  • An angle bisector is equidistant from the sides of the angle when measured along a segment perpendicular to the sides of the angle.
  • It cuts the angle into half.
  • Thus, a sector can be divided into two equal sectors by drawing an angle bisector.

To divide the sector into two congruent sectors we can use the angle bisector construction.

Thus, the correct answer is

Option A) angle bisector

4 0
3 years ago
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