<h3>
Answer: B) Only the first equation is an identity</h3>
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I'm using x in place of theta. For each equation, I'm only altering the left hand side.
Part 1
cos(270+x) = sin(x)
cos(270)cos(x) - sin(270)sin(x) = sin(x)
0*cos(x) - (-1)*sin(x) = sin(x)
0 + sin(x) = sin(x)
sin(x) = sin(x) ... equation is true
Identity is confirmed
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Part 2
sin(270+x) = -sin(x)
sin(270)cos(x) + cos(270)sin(x) = -sin(x)
-1*cos(x) + 0*sin(x) = -sin(x)
-cos(x) = -sin(x)
We don't have an identity. If the right hand side was -cos(x), instead of -sin(x), then we would have an identity.
The answer is 45
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Answer:
D. 2x²
Step-by-step explanation:
Ok, so the first thing to do is remember the first number in parentheses is x, and the second number is y.
You're trying to figure out which expression turns x into y in each set.
Just by plugging in the numbers into each expression I found that the answer is 2x².
I'll prove this starting with (1, 2).
1² = 1
2 x 1 = 2
So, y = 2x²!
Next, (2, 8).
2² = 4
2 x 4 = 8
So, y = 2x²!
I'm not going to demonstrate with the other two but I hope you understand. Just plug the values of x and y into the equation and see which is correct.
Answer:
Step-by-step explanation:
Since log is defined by all positive real numbers
therefore domain is all positive real number that is ( 0,∞)
Range is given by real numbers
inverse of the given function is (10^x)/7
Whose domain is all real numbers and range is all positive real number
And since we know that domain of function and range of its inverse
& range of a function and domain of its inverse is same
which we are getting in the problem
so answer is justified
