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asambeis [7]
3 years ago
12

True or false a plane contains only three points

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
7 0

Answer:

Step-by-step explanation:

True.

Lisa [10]3 years ago
5 0

Answer:

The correct answer is true. A plane formation conditions are: 1) At least three non-collinear points. 2) At least one point and a straight line such that the point should not lie on the straight line. This is the criteria for plane formation

Hope this helps :)

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Can someone help me ?
denis23 [38]

Answer:

r = - 29

Step-by-step explanation:

Given

- 3r = 87 ( divide both sides by - 3 )

r = \frac{87}{-3} = - 29

7 0
3 years ago
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The area of a square is 72.25 inches squared. Find the length of the side and the perimeter.
Darina [25.2K]

Area of the square = 72.25

side^2 = 72.25

side = \sqrt{72.25}

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morpeh [17]
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Help!!!!!!!!!!!!!!!!​
kaheart [24]

Answer:

\cos\alpha\sin\alpha(\cos\alpha-\sin\alpha)

Step-by-step explanation:

First, simplify each term:

\sin\left(\dfrac{\pi}{2}+\alpha\right)=\cos \alpha\\ \\\cos \left(\dfrac{\pi}{2}+\alpha\right)=-\sin \alpha\\ \\\cos \left(\alpha-\dfrac{3\pi}{2}\right)=-\sin \alpha\\ \\\sin \left(\dfrac{3\pi}{2}+\alpha\right)=-\cos \alpha

Then given expression is equivalent to

\cos ^3\alpha+(-\sin \alpha)^3-(-\sin \alpha)+(-\cos \alpha)\\ \\=\cos ^3\alpha-\sin^3 \alpha+\sin \alpha-\cos \alpha\\ \\=(\cos\alpha-\sin\alpha)(\cos^2\alpha+\cos\alpha\sin\alpha+\sin^2\alpha)-(\cos\alpha-\sin\alpha)\\ \\=(\cos\alpha-\sin\alpha)(1+\cos\alpha\sin\alpha-1)\ \ [\cos^2\alpha+\sin^2\alpha=1]\\ \\=\cos\alpha\sin\alpha(\cos\alpha-\sin\alpha)

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Step-by-step explanation:

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