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3 years ago

Find two points on the x-axis that are 13 units from (2, 12).

Mathematics

1 answer:

dsp733 years ago

5 0

5 Are you good in geometry I can do this fort you if do my question about geometry

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(n2+11n+25) ÷ ( n+5) long division

zmey [24]

Answer:

$(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}$ or $n+6,R5$

Step-by-step explanation:

Synthetic division:

-5 | 1 11 25

____-5 -30

1 6 | -5

Therefore, $(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}$ or $n+6,_$R$5$

Long division:

n+5 | n² + 11n + 25

- n² + 5n____ <-- n

6n + 25

- 6n + 30 <-- 6

-5 | n+6

Therefore, $(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}$ or $n+6,_$R$5$

6 0

3 years ago

Which equation has a wider graph than y=1/7x^2

svp [43]

Y = 2x^2 has a wider graph

7 0

3 years ago

Simplify: [5×(25)^n+1 - 25 × (5)^2n]/[5×(5)^2n+3 - (25)^n+1]

Alekssandra [29.7K]

$\green{\large\underline{\sf{Solution-}}}$

Given expression is 

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

Hence, 

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

4 0

3 years ago

Kathy ran the 400-meter dash in 60.48 seconds. She ran the 200 meter dash in 28.9 seconds.If she divided her 400-meter dash time

nika2105 [10]

Answer:

Kathy would take 7.56 seconds to run each of the 8-time segments of the 400-meter dash.

Step-by-step explanation:

Kathy ran the 400-meter dash in 60.48 seconds, so if she now divided that time into 8 equal time segments we have:

$t = 60.48 s$

By dividing the above equation into 8:

$t = \frac{60.48 s}{8} = 7.56 s$

Hence, she would take 7.56 seconds to run each of the 8-time segments of the 400-meter dash.

I hope it helps you!

3 0

3 years ago

a Radioactive material has a half life of 18.4 days. How Much Time Is Needed For A 50 mg sample to decay to 12.5 mg?

AnnZ [28]

36.8 days is the answer to your question

6 0

4 years ago

Find two points on the x-axis that are 13 units from (2, 12).​

Find two points on the x-axis that are 13 units from (2, 12).