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kupik [55]
3 years ago
15

Bella measured these outside temperatures for each of four days.

Mathematics
1 answer:
kap26 [50]3 years ago
4 0
What is the complete question and what are the choices??
You might be interested in
Plz help, 15 points!
Eduardwww [97]

Answer:

2x+3y=-6

Step-by-step explanation:

Let the line is y=mx+b where m is slope and b is y-intercept.

The line is parallel to 2x+3y=3, slope of both the lines will be same.

Find the slope of 2x+3y=3

3y=3-2x\\y=-\frac{2}{3}x+1

Slope of line=-\frac{2}{3}

m=-\frac{2}{3}

So the line will be y=-\frac{2}{3}x+b

It passes through (3,-4).

-4=-\frac{2}{3}\times 3+b\\-4=-2+b\\b=-2\\

Hence the line is y=-\frac{2}{3}x-2

y=-\frac{2}{3}x-2\\3y=-2x-6\ \ \ \ \ \ \ (Multiply both sides by 3)\\2x+3y=-6

6 0
3 years ago
Which is equivalent to 3 cube root 125
aleksklad [387]
Do you mean 3 \sqrt[3]{125} or \sqrt[3]{125}
remember that \sqrt[n]{x^m}=x^\frac{m}{n}
resolve the \sqrt[3]{125} part first\sqrt[3]{125}=\sqrt[3]{5^3}=5^\frac{3}{3}=5^1=5

so
3 \sqrt[3]{125}=3*5=15 or \sqrt[3]{125} =5not sure which one you mean
7 0
3 years ago
Read 2 more answers
Points W and V create WV¯¯¯¯¯¯¯¯¯. Point W is located at (−6,−6) and point V is located at (−6,−2) Imagine WV¯¯¯¯¯¯¯¯¯ is rotate
Ratling [72]

Answer:

Points W and V create WV¯¯¯¯¯¯¯¯¯. Point W is located at (−6,−6) and point V is located at (−6,−2) Imagine WV¯¯¯¯¯¯¯¯¯ is rotated 180∘ clockwise about the origin. Answer the following questions about W′V′¯¯¯¯¯¯¯¯¯¯¯¯¯.

A: What are the coordinates of point W′?

B: What are the coordinates of point V′?

Select two answers: one for Question A and one for Question B.

B: (6,−2)

A: (6,6)

B: (6,2)

B: (−6,6)

B: (6,6)

A: (−6,2)

A: (6,−6)

A: (6,2)

Step-by-step explanation:

duh

8 0
3 years ago
In the figure below, which angle pair is a pair of corresponding angles?
Hoochie [10]
The answer is D. Angle 4 and angle 8 are corresponding...
6 0
3 years ago
Read 2 more answers
Write a quadratic equation ax²+ bx + C = 0, whose coefficients are a =-9, b = 0, c = -2
aksik [14]
<h3>ax² + bx + c = 0</h3>

<em>Let's write -9 where we see A</em><em>:</em>

<h3>-9x² + bx + c = 0</h3>

<em>Let's</em><em> </em><em>write</em><em> </em><em>0</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>B</em><em>:</em>

<h3>-9x² + 0.x + c = 0</h3>

<em>(</em><em>Since B = 0, when it is multiplied by x, it becomes 0 again</em><em>)</em>

<h3>-9x² + c = 0</h3>

<em>Let's</em><em> </em><em>write</em><em> </em><em>-2</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>C</em><em>:</em>

<h3>-9x² + -2 = 0</h3>

<em>Now we can move on to solving our equation</em><em>:</em><em>)</em>

<em>Let's put the known and the unknown on different sides:</em>

<em>(</em><em>-2 goes to the opposite side positively</em><em>)</em>

<h3>-9x² = 2</h3>

<em>(</em><em>i</em><em>t goes as a division because it is in the case of multiplying -9 across</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<h3>x² = 2/-9</h3>

<em>I could not find the rest of it, but I did not want to delete it for trying very hard. Sorry. It felt like we should take the square root, but I couldn't find it, maybe this can help you a little bit.</em>

<em>Please do not report</em><em>:</em><em>(</em>

<em>I hope I got it right, I'm trying to improve my English a little :)</em>

<h3><em>Greetings from Turke</em><em>y</em><em>:</em><em>)</em></h3>

<h3><em><u>#XBadeX</u></em></h3>
8 0
3 years ago
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