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lukranit [14]
2 years ago
6

What is the area of the triangle formed from (-2,2), (1,2) and (0,-6)

Mathematics
1 answer:
Aleks04 [339]2 years ago
5 0

Answer:

I think it's 12

Step-by-step explanation:

Hope it helps!

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It is estimated 30% of all adults in United States invest in stocks and that 84% of U.S. adults have investments in fixed
lana66690 [7]

Answer:

=109%

Step-by-step explanation:

6 0
3 years ago
Mariah builds a tabletop using square tiles, There are 12 rows of tiles and 30 tiles in each row. How many tiles does Mariah use
kiruha [24]
360 tiles because you have to multiply 12x30.
4 0
3 years ago
Make t the subject of k= t-e/2
Sophie [7]

Answer:

t=k+\frac{e}{2}

Step-by-step explanation:

k=t-\frac{e}{2}\\t=k+\frac{e}{2}

5 0
2 years ago
Lee needed to make drapes the length from the floor to the top of the window. The wall beneath the window had the height of 2 2/
Tatiana [17]
Since drapes have to be covered all over the window and the beneath of the window, both lengths have to be added.

(2 2/3) + ( 2 3/4) 
(8/3) + (11/4)
(32+33)/12
65/12
5 5/12
7 0
3 years ago
Explain the steps to finding the vertex of g(x) = 3x2 + 12x + 15
RUDIKE [14]

Answer:

The vertex of this parabola, (-2, 3), can be found by completing the square.

Step-by-step explanation:

The goal is to express this parabola in its vertex form:

g(x) = a\, (x - h)^2 + k,

where a, h, and k are constants. Once these three constants were found, it can be concluded that the vertex of this parabola is at (h,\, k).

The vertex form can be expanded to obtain:

\begin{aligned}g(x)&= a\, (x - h)^2 + k \\ &= a\, \left(x^2 - 2\, x\, h + h^2\right) + k = a\, x^2 - 2\, a\, h\, x + \left(a\,h^2 + k\right)\end{aligned}.

Compare that expression with the given equation of this parabola. The constant term, the coefficient for x, and the coefficient for x^2 should all match accordingly. That is:

\left\lbrace\begin{aligned}& a = 3 \\ & -2\,a\, h = 12 \\& a\, h^2 + k = 15\end{aligned}\right..

The first equation implies that a is equal to 3. Hence, replace the "a\!" in the second equation with 3\! to eliminate \! a:

(-2\times 3)\, h = 12.

h = -2.

Similarly, replace the "a" and the "h" in the third equation with 3 and (-2), respectively:

3 \times (-2)^2 + k = 15.

k = 3.

Therefore, g(x) = 3\, x^2 + 12\, x + 15 would be equivalent to g(x) = 3\, (x - (-2))^2 + 3. The vertex of this parabola would thus be:

\begin{aligned}&(-2, \, 3)\\ &\phantom{(}\uparrow \phantom{,\,} \uparrow \phantom{)} \\ &\phantom{(}\; h \phantom{,\,} \;\;k\end{aligned}.

8 0
3 years ago
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