This depends on what the shape is.
Cube: 6(l*w)
Rectangular Prism: 2(lw) + 2(wh) + w(lh)
It goes on....
Use PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
[(30 + 6) - 32] : 9 · 2 = (36 - 32) : 9 · 2 = 4 : 9 · 2 = 4/9 · 2 = 8/9
Answer:
This is already as simple as it will get. You could expand it though. In that case you'd get:
(x + y)⁴
= (x² + 2xy + y²)²
= x⁴ + 2x³y + x²y² + 2x³y + 4x²y² + 2xy³ + x²y² + 2xy³ + y⁴
= x⁴ + 4x³y + 6x²y² +4xy³ + y⁴
But this doesn't simplify at all.
The number are you answer
Yes. This equation given:
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" y = (½)x + 4 " ; in point-slope form; also known as: "slope-intercept form" ; is:
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" y = (½)x + 4 " .
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In other words, the equation given is ALREADY written in "point-slope form" ; or, "slope-intercept form".
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Note: An equation that is written in "point-slope form"
(or, "slope-intercept form"), is written in the format of:
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" y = mx + b " ;_________________
in which:_________________
"y" is a single, "stand-alone" variable on the "left-hand side of the equation"; "m" is the coefficient of "x"; also:
"m" is the slope of the line; which is what we want to solve for;
"b" is the "y-intercept"; or more precisely, the value of "x"
(that is; the "x-coordinate") of the point at which "y = 0";
that is, the value of "x" ; or the "x-coordinate" of the point at which
the graph of the equation crosses the "x-axis".
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Note that in our given equation, which is written in "point-slope form" (or, "slope-intercept form" — that is: " y = mx + b " ;
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which is: " y = (½)x + 4 " ;
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we have:
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"y" isolated as "stand-alone" variable on the "left-hand side" of the equation;
m = ½ ;
b = 4 .
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